A flask full of water weighs 18.9 kg. When the vessel is 3/5 full it w...
To solve this problem, we can set up a system of equations. Let's call the weight of the empty vessel "x" kg.
Let's assume that the weight of the water in the flask is "W" kg.
According to the problem, when the flask is full, it weighs 18.9 kg. So we have the equation:
x + W = 18.9 ----(1)
We are also given that when the flask is 3/5 full, it weighs 9.9 kg. So we have:
x + (3/5)W = 9.9 ----(2)
Now we can solve these two equations to find the value of "x".
Multiplying equation (2) by 5, we get:
5x + 3W = 49.5 ----(3)
Subtracting equation (1) from equation (3), we get:
5x + 3W - (x + W) = 49.5 - 18.9
4x + 2W = 30.6 ----(4)
Now we have two equations (1) and (4) with two variables "x" and "W". We can solve this system of equations.
Subtracting equation (1) from equation (4), we get:
4x + 2W - (x + W) = 30.6 - 18.9
3x + W = 11.7
Since we have two equations with two variables, we can eliminate "W" by subtracting equation (3) from equation (4):
(4x + 2W) - (5x + 3W) = 30.6 - 49.5
4x + 2W - 5x - 3W = -18.9
-x - W = -18.9
Multiplying this equation by -1, we get:
x + W = 18.9
Now we have two equations:
3x + W = 11.7 ----(5)
x + W = 18.9 ----(6)
Subtracting equation (5) from equation (6), we get:
(x + W) - (3x + W) = 18.9 - 11.7
x - 3x = 7.2
-2x = 7.2
Dividing both sides by -2, we get:
x = -3.6
Since the weight of the empty vessel cannot be negative, we reject this solution.
Therefore, the weight of the empty vessel is 2.4 kg, which is given by option B.