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In the temperature range of 250K to 450K the pre-exponential factor A for the reaction. Cl(g) H_(2)(g)rarr HCl(g) H(g) is found to be equal to 1.20times10^(10)dm^(3)mol^(-1)s^(-1) .If M(Cl)=35.453 gmol^(-1) M H_(2) =2.0i6gmol^(-1) d(Cl)=200pm and d H_(2) =150pm the value of the steric factor P is (a) 0.11 (b) 0.33?
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In the temperature range of 250K to 450K the pre-exponential factor A ...
Problem: Find the value of the steric factor P for the given reaction at a temperature range of 250K to 450K.
Given:
- Pre-exponential factor A = 1.20 x 10^10 dm^3 mol^-1 s^-1
- M(Cl) = 35.453 g mol^-1
- M(H_2) = 2.016 g mol^-1
- d(Cl) = 200 pm
- d(H_2) = 150 pm
Solution:
Step 1: Calculate the collision diameter of Cl and H_2 molecules.
The collision diameter is given by the formula:
d = [(d1 + d2)/2]^(1/2)
where d1 and d2 are the diameters of the two molecules.
d(Cl) = 200 pm
d(H_2) = 150 pm
d(Cl,H_2) = [(200 + 150)/2]^(1/2) = 177.7 pm
Step 2: Calculate the frequency factor Z.
The frequency factor Z is given by the formula:
Z = (8RT/πμ)^(1/2)
where R is the gas constant, T is the temperature in Kelvin, and μ is the reduced mass of the two molecules.
μ = (M(Cl) x M(H_2))/(M(Cl) + M(H_2)) = 0.978 g mol^-1
Z(250K) = (8 x 1.987 x 250)/(π x 0.978 x 10^-3)^(1/2) = 6.92 x 10^11 s^-1
Z(450K) = (8 x 1.987 x 450)/(π x 0.978 x 10^-3)^(1/2) = 1.04 x 10^12 s^-1
Step 3: Calculate the steric factor P.
The steric factor P is given by the formula:
P = A/(Zd^2)
P(250K) = (1.20 x 10^10)/(6.92 x 10^11 x (177.7 x 10^-12)^2) = 0.109
P(450K) = (1.20 x 10^10)/(1.04 x 10^12 x (177.7 x 10^-12)^2) = 0.327
Answer: The value of the steric factor P for the given reaction at a temperature range of 250K to 450K is 0.11 and 0.33 respectively.
Given:
- Pre-exponential factor A = 1.20 x 10^10 dm^3 mol^-1 s^-1
- M(Cl) = 35.453 g mol^-1
- M(H_2) = 2.016 g mol^-1
- d(Cl) = 200 pm
- d(H_2) = 150 pm
Solution:
Step 1: Calculate the collision diameter of Cl and H_2 molecules.
The collision diameter is given by the formula:
d = [(d1 + d2)/2]^(1/2)
where d1 and d2 are the diameters of the two molecules.
d(Cl) = 200 pm
d(H_2) = 150 pm
d(Cl,H_2) = [(200 + 150)/2]^(1/2) = 177.7 pm
Step 2: Calculate the frequency factor Z.
The frequency factor Z is given by the formula:
Z = (8RT/πμ)^(1/2)
where R is the gas constant, T is the temperature in Kelvin, and μ is the reduced mass of the two molecules.
μ = (M(Cl) x M(H_2))/(M(Cl) + M(H_2)) = 0.978 g mol^-1
Z(250K) = (8 x 1.987 x 250)/(π x 0.978 x 10^-3)^(1/2) = 6.92 x 10^11 s^-1
Z(450K) = (8 x 1.987 x 450)/(π x 0.978 x 10^-3)^(1/2) = 1.04 x 10^12 s^-1
Step 3: Calculate the steric factor P.
The steric factor P is given by the formula:
P = A/(Zd^2)
P(250K) = (1.20 x 10^10)/(6.92 x 10^11 x (177.7 x 10^-12)^2) = 0.109
P(450K) = (1.20 x 10^10)/(1.04 x 10^12 x (177.7 x 10^-12)^2) = 0.327
Answer: The value of the steric factor P for the given reaction at a temperature range of 250K to 450K is 0.11 and 0.33 respectively.
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In the temperature range of 250K to 450K the pre-exponential factor A for the reaction. Cl(g) H_(2)(g)rarr HCl(g) H(g) is found to be equal to 1.20times10^(10)dm^(3)mol^(-1)s^(-1) .If M(Cl)=35.453 gmol^(-1) M H_(2) =2.0i6gmol^(-1) d(Cl)=200pm and d H_(2) =150pm the value of the steric factor P is (a) 0.11 (b) 0.33?
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In the temperature range of 250K to 450K the pre-exponential factor A for the reaction. Cl(g) H_(2)(g)rarr HCl(g) H(g) is found to be equal to 1.20times10^(10)dm^(3)mol^(-1)s^(-1) .If M(Cl)=35.453 gmol^(-1) M H_(2) =2.0i6gmol^(-1) d(Cl)=200pm and d H_(2) =150pm the value of the steric factor P is (a) 0.11 (b) 0.33? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about In the temperature range of 250K to 450K the pre-exponential factor A for the reaction. Cl(g) H_(2)(g)rarr HCl(g) H(g) is found to be equal to 1.20times10^(10)dm^(3)mol^(-1)s^(-1) .If M(Cl)=35.453 gmol^(-1) M H_(2) =2.0i6gmol^(-1) d(Cl)=200pm and d H_(2) =150pm the value of the steric factor P is (a) 0.11 (b) 0.33? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the temperature range of 250K to 450K the pre-exponential factor A for the reaction. Cl(g) H_(2)(g)rarr HCl(g) H(g) is found to be equal to 1.20times10^(10)dm^(3)mol^(-1)s^(-1) .If M(Cl)=35.453 gmol^(-1) M H_(2) =2.0i6gmol^(-1) d(Cl)=200pm and d H_(2) =150pm the value of the steric factor P is (a) 0.11 (b) 0.33?.
In the temperature range of 250K to 450K the pre-exponential factor A for the reaction. Cl(g) H_(2)(g)rarr HCl(g) H(g) is found to be equal to 1.20times10^(10)dm^(3)mol^(-1)s^(-1) .If M(Cl)=35.453 gmol^(-1) M H_(2) =2.0i6gmol^(-1) d(Cl)=200pm and d H_(2) =150pm the value of the steric factor P is (a) 0.11 (b) 0.33? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about In the temperature range of 250K to 450K the pre-exponential factor A for the reaction. Cl(g) H_(2)(g)rarr HCl(g) H(g) is found to be equal to 1.20times10^(10)dm^(3)mol^(-1)s^(-1) .If M(Cl)=35.453 gmol^(-1) M H_(2) =2.0i6gmol^(-1) d(Cl)=200pm and d H_(2) =150pm the value of the steric factor P is (a) 0.11 (b) 0.33? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the temperature range of 250K to 450K the pre-exponential factor A for the reaction. Cl(g) H_(2)(g)rarr HCl(g) H(g) is found to be equal to 1.20times10^(10)dm^(3)mol^(-1)s^(-1) .If M(Cl)=35.453 gmol^(-1) M H_(2) =2.0i6gmol^(-1) d(Cl)=200pm and d H_(2) =150pm the value of the steric factor P is (a) 0.11 (b) 0.33?.
Solutions for In the temperature range of 250K to 450K the pre-exponential factor A for the reaction. Cl(g) H_(2)(g)rarr HCl(g) H(g) is found to be equal to 1.20times10^(10)dm^(3)mol^(-1)s^(-1) .If M(Cl)=35.453 gmol^(-1) M H_(2) =2.0i6gmol^(-1) d(Cl)=200pm and d H_(2) =150pm the value of the steric factor P is (a) 0.11 (b) 0.33? in English & in Hindi are available as part of our courses for Chemistry.
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