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Upper boundary of any class coincides with the lower boundary of the next class. 
  • a)
    True 
  • b)
    False 
  • c)
    Both 
  • d)
    None 
Correct answer is option 'A'. Can you explain this answer?
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Upper boundary of any class coincides with the lower boundary of the n...
Upper boundary of any class coincides with the lower boundary of the next class.

Explanation:

This statement is true in the case of Continuous Frequency Distribution. Continuous Frequency Distribution is a probability distribution that has an infinite number of possible values within a certain range. In Continuous Frequency Distribution, the data is grouped into classes or intervals. Each class has an upper boundary and a lower boundary.

The upper boundary of any class is the maximum value that belongs to that class, while the lower boundary is the minimum value that belongs to that class. The lower boundary of any class coincides with the upper boundary of the previous class, and the upper boundary of any class coincides with the lower boundary of the next class.

This is because there is no gap or overlap between the classes in Continuous Frequency Distribution. The classes are continuous and they form a continuous sequence. Therefore, the upper boundary of one class is also the lower boundary of the next class.

For example, if we have a Continuous Frequency Distribution with classes of width 5, and the first class starts from 0, then the upper boundary of the first class is 4, and the lower boundary of the second class is also 4. The upper boundary of the second class is 9, and the lower boundary of the third class is also 9, and so on.

Conclusion:

In conclusion, the upper boundary of any class coincides with the lower boundary of the next class in Continuous Frequency Distribution. This concept is important in statistics, especially in constructing histograms and frequency polygons.
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Upper boundary of any class coincides with the lower boundary of the next class.a)Trueb)Falsec)Bothd)NoneCorrect answer is option 'A'. Can you explain this answer?
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