Electrolysis of a solution of HSO4- ions produces S2O8andndash; andndash;. Assuming 75% current efficiency, what current should be employed to achieve a production rate of 1 mole of S2O8- - per hour ?a)71.48 Ab)35.7 Ac)142.96 Ad)285.93 ACorrect answer is option 'A'. Can you explain this answer?

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Electrolysis of a solution of HSO₄^- ions produces S₂O₈^{– –}. Assuming 75% current efficiency, what current should be employed to achieve a production rate of 1 mole of S₂O₈^{- -} per hour ?

a)
71.48 A
b)
35.7 A
c)
142.96 A
d)
285.93 A

Correct answer is option 'A'. Can you explain this answer?

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Electrolysis of a solution of HSO4- ions produces S2O8– –....

2- ions and H2 gas.

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Electrolysis of a solution of HSO4- ions produces S2O8– –. Assuming 75% current efficiency, what current should be employed to achieve a production rate of 1 mole of S2O8- - per hour ?a)71.48 Ab)35.7 Ac)142.96 Ad)285.93 ACorrect answer is option 'A'. Can you explain this answer?

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Electrolysis of a solution of HSO4- ions produces S2O8– –. Assuming 75% current efficiency, what current should be employed to achieve a production rate of 1 mole of S2O8- - per hour ?a)71.48 Ab)35.7 Ac)142.96 Ad)285.93 ACorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Electrolysis of a solution of HSO4- ions produces S2O8– –. Assuming 75% current efficiency, what current should be employed to achieve a production rate of 1 mole of S2O8- - per hour ?a)71.48 Ab)35.7 Ac)142.96 Ad)285.93 ACorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Electrolysis of a solution of HSO4- ions produces S2O8– –. Assuming 75% current efficiency, what current should be employed to achieve a production rate of 1 mole of S2O8- - per hour ?a)71.48 Ab)35.7 Ac)142.96 Ad)285.93 ACorrect answer is option 'A'. Can you explain this answer?.

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