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A current of 2.68 A is passed for one hour through an aqueous solution of CuSO4 using copper electrodes . Select the correct statement(s) from the following :
  • a)
    increase in mass of cathode = 3.174 g    
  • b)
    decrease in mass of anode = 3.174 g
  • c)
    no change in masses of electrodes        
  • d)
    the ratio between the change of masses of cathode and anode is 1 : 2 .
Correct answer is option 'A,B'. Can you explain this answer?
Verified Answer
A current of 2.68 A is passed for one hour through an aqueous solution...
Increase in mass of cathode = decrease in mass of Anode =
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Most Upvoted Answer
A current of 2.68 A is passed for one hour through an aqueous solution...
Explanation:

Given Data:
- Current passed = 2.68 A
- Time = 1 hour
- Aqueous solution = CuSO4
- Electrodes = Copper

Calculation of Mass Changes:
- Using Faraday's laws of electrolysis, we can calculate the mass changes at the electrodes.
- The equation for calculating the mass change is: Mass change = (Current x Time x Molar mass) / (n x Faraday's constant)
- For copper electrodes, the molar mass of Cu is 63.5 g/mol and the charge transferred per mole of Cu is 2 (n = 2)

Calculation for Cathode:
- Mass change at cathode = (2.68 A x 3600 s x 63.5 g/mol) / (2 x 96500 C/mol)
- Mass change at cathode = 3.174 g

Calculation for Anode:
- Mass change at anode = -3.174 g (since it is the opposite of cathode)

Conclusion:
- The correct statements are:
a) Increase in mass of cathode = 3.174 g
b) Decrease in mass of anode = 3.174 g
Therefore, options A and B are correct based on the calculations using Faraday's laws of electrolysis.
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Community Answer
A current of 2.68 A is passed for one hour through an aqueous solution...
Increase in mass of cathode = decrease in mass of Anode =
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A current of 2.68 A is passed for one hour through an aqueous solution of CuSO4 using copper electrodes . Select the correct statement(s) from the following :a)increase in mass of cathode = 3.174 g b)decrease in mass of anode = 3.174 gc)no change in masses of electrodes d)the ratio between the change of masses of cathode and anode is 1 : 2 .Correct answer is option 'A,B'. Can you explain this answer?
Question Description
A current of 2.68 A is passed for one hour through an aqueous solution of CuSO4 using copper electrodes . Select the correct statement(s) from the following :a)increase in mass of cathode = 3.174 g b)decrease in mass of anode = 3.174 gc)no change in masses of electrodes d)the ratio between the change of masses of cathode and anode is 1 : 2 .Correct answer is option 'A,B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A current of 2.68 A is passed for one hour through an aqueous solution of CuSO4 using copper electrodes . Select the correct statement(s) from the following :a)increase in mass of cathode = 3.174 g b)decrease in mass of anode = 3.174 gc)no change in masses of electrodes d)the ratio between the change of masses of cathode and anode is 1 : 2 .Correct answer is option 'A,B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A current of 2.68 A is passed for one hour through an aqueous solution of CuSO4 using copper electrodes . Select the correct statement(s) from the following :a)increase in mass of cathode = 3.174 g b)decrease in mass of anode = 3.174 gc)no change in masses of electrodes d)the ratio between the change of masses of cathode and anode is 1 : 2 .Correct answer is option 'A,B'. Can you explain this answer?.
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