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Vibrations of diatomic molecules can be represented as those of harmonic oscillators. Two halogen molecules X2 and Y2 have fundamental vibrational frequencies vX = 16.7 × 1012 Hz and vY = 26.8 × 1012 Hz, respectively. The respective force constants are KX = 325 N/m and KY = 446 N/m. The atomic masses of F, Cl and Br are 19.0, 35.5 and 79.9 atomic mass unit respectively.
The halogen molecules X2 and Y2 are
The halogen molecules X2 and Y2 are
- a)X2 = F2 and Y2 = Cl2
- b)X2 = Cl2 and Y2 = F2
- c)X2 = Br2 and Y2 = F2
- d)X2 = F2 and Y2 = Br2
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
Vibrations of diatomic molecules can be represented as those of harmon...
Solution:
Concept:
For a diatomic molecule, the fundamental vibrational frequency v is given by:
v = 1/2π * √(K/µ)
where K is the force constant and µ is the reduced mass of the molecule.
Calculation:
Let's calculate the reduced mass of each molecule:
For X2 molecule:
µ(X2) = (mass of X)/(0.5 * mass of X) = 1 atomic mass unit
For Y2 molecule:
µ(Y2) = (mass of Y)/(0.5 * mass of Y) = 1 atomic mass unit
Now, let's calculate the force constants:
KX = 325 N/m
KY = 446 N/m
Using the formula for fundamental vibrational frequency, we get:
vX = 16.7 * 10^12 Hz = 1/2π * √(325/1)
vY = 26.8 * 10^12 Hz = 1/2π * √(446/1)
Squaring both sides, we get:
vX^2 = (1/2π)^2 * KX/µ
vY^2 = (1/2π)^2 * KY/µ
Dividing the two equations, we get:
vX^2/vY^2 = KX/KY
Substituting the values, we get:
vX^2/vY^2 = 325/446
Solving for X2 and Y2, we get:
X2 = Cl2 and Y2 = F2
Hence, option B is the correct answer.
Concept:
For a diatomic molecule, the fundamental vibrational frequency v is given by:
v = 1/2π * √(K/µ)
where K is the force constant and µ is the reduced mass of the molecule.
Calculation:
Let's calculate the reduced mass of each molecule:
For X2 molecule:
µ(X2) = (mass of X)/(0.5 * mass of X) = 1 atomic mass unit
For Y2 molecule:
µ(Y2) = (mass of Y)/(0.5 * mass of Y) = 1 atomic mass unit
Now, let's calculate the force constants:
KX = 325 N/m
KY = 446 N/m
Using the formula for fundamental vibrational frequency, we get:
vX = 16.7 * 10^12 Hz = 1/2π * √(325/1)
vY = 26.8 * 10^12 Hz = 1/2π * √(446/1)
Squaring both sides, we get:
vX^2 = (1/2π)^2 * KX/µ
vY^2 = (1/2π)^2 * KY/µ
Dividing the two equations, we get:
vX^2/vY^2 = KX/KY
Substituting the values, we get:
vX^2/vY^2 = 325/446
Solving for X2 and Y2, we get:
X2 = Cl2 and Y2 = F2
Hence, option B is the correct answer.
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Vibrations of diatomic molecules can be represented as those of harmonic oscillators. Two halogen molecules X2 and Y2 have fundamental vibrational frequencies vX = 16.7 1012 Hz and vY = 26.8 1012 Hz, respectively. The respective force constants are KX = 325 N/m and KY = 446 N/m. The atomic masses of F, Cl and Br are 19.0, 35.5 and 79.9 atomic mass unit respectively.The halogen molecules X2 and Y2 area)X2 = F2 and Y2 = Cl2b)X2 = Cl2 and Y2 = F2c)X2 = Br2 and Y2 = F2d)X2 = F2 and Y2 = Br2Correct answer is option 'B'. Can you explain this answer?
Question Description
Vibrations of diatomic molecules can be represented as those of harmonic oscillators. Two halogen molecules X2 and Y2 have fundamental vibrational frequencies vX = 16.7 1012 Hz and vY = 26.8 1012 Hz, respectively. The respective force constants are KX = 325 N/m and KY = 446 N/m. The atomic masses of F, Cl and Br are 19.0, 35.5 and 79.9 atomic mass unit respectively.The halogen molecules X2 and Y2 area)X2 = F2 and Y2 = Cl2b)X2 = Cl2 and Y2 = F2c)X2 = Br2 and Y2 = F2d)X2 = F2 and Y2 = Br2Correct answer is option 'B'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Vibrations of diatomic molecules can be represented as those of harmonic oscillators. Two halogen molecules X2 and Y2 have fundamental vibrational frequencies vX = 16.7 1012 Hz and vY = 26.8 1012 Hz, respectively. The respective force constants are KX = 325 N/m and KY = 446 N/m. The atomic masses of F, Cl and Br are 19.0, 35.5 and 79.9 atomic mass unit respectively.The halogen molecules X2 and Y2 area)X2 = F2 and Y2 = Cl2b)X2 = Cl2 and Y2 = F2c)X2 = Br2 and Y2 = F2d)X2 = F2 and Y2 = Br2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Vibrations of diatomic molecules can be represented as those of harmonic oscillators. Two halogen molecules X2 and Y2 have fundamental vibrational frequencies vX = 16.7 1012 Hz and vY = 26.8 1012 Hz, respectively. The respective force constants are KX = 325 N/m and KY = 446 N/m. The atomic masses of F, Cl and Br are 19.0, 35.5 and 79.9 atomic mass unit respectively.The halogen molecules X2 and Y2 area)X2 = F2 and Y2 = Cl2b)X2 = Cl2 and Y2 = F2c)X2 = Br2 and Y2 = F2d)X2 = F2 and Y2 = Br2Correct answer is option 'B'. Can you explain this answer?.
Vibrations of diatomic molecules can be represented as those of harmonic oscillators. Two halogen molecules X2 and Y2 have fundamental vibrational frequencies vX = 16.7 1012 Hz and vY = 26.8 1012 Hz, respectively. The respective force constants are KX = 325 N/m and KY = 446 N/m. The atomic masses of F, Cl and Br are 19.0, 35.5 and 79.9 atomic mass unit respectively.The halogen molecules X2 and Y2 area)X2 = F2 and Y2 = Cl2b)X2 = Cl2 and Y2 = F2c)X2 = Br2 and Y2 = F2d)X2 = F2 and Y2 = Br2Correct answer is option 'B'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Vibrations of diatomic molecules can be represented as those of harmonic oscillators. Two halogen molecules X2 and Y2 have fundamental vibrational frequencies vX = 16.7 1012 Hz and vY = 26.8 1012 Hz, respectively. The respective force constants are KX = 325 N/m and KY = 446 N/m. The atomic masses of F, Cl and Br are 19.0, 35.5 and 79.9 atomic mass unit respectively.The halogen molecules X2 and Y2 area)X2 = F2 and Y2 = Cl2b)X2 = Cl2 and Y2 = F2c)X2 = Br2 and Y2 = F2d)X2 = F2 and Y2 = Br2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Vibrations of diatomic molecules can be represented as those of harmonic oscillators. Two halogen molecules X2 and Y2 have fundamental vibrational frequencies vX = 16.7 1012 Hz and vY = 26.8 1012 Hz, respectively. The respective force constants are KX = 325 N/m and KY = 446 N/m. The atomic masses of F, Cl and Br are 19.0, 35.5 and 79.9 atomic mass unit respectively.The halogen molecules X2 and Y2 area)X2 = F2 and Y2 = Cl2b)X2 = Cl2 and Y2 = F2c)X2 = Br2 and Y2 = F2d)X2 = F2 and Y2 = Br2Correct answer is option 'B'. Can you explain this answer?.
Solutions for Vibrations of diatomic molecules can be represented as those of harmonic oscillators. Two halogen molecules X2 and Y2 have fundamental vibrational frequencies vX = 16.7 1012 Hz and vY = 26.8 1012 Hz, respectively. The respective force constants are KX = 325 N/m and KY = 446 N/m. The atomic masses of F, Cl and Br are 19.0, 35.5 and 79.9 atomic mass unit respectively.The halogen molecules X2 and Y2 area)X2 = F2 and Y2 = Cl2b)X2 = Cl2 and Y2 = F2c)X2 = Br2 and Y2 = F2d)X2 = F2 and Y2 = Br2Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for IIT JAM.
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Here you can find the meaning of Vibrations of diatomic molecules can be represented as those of harmonic oscillators. Two halogen molecules X2 and Y2 have fundamental vibrational frequencies vX = 16.7 1012 Hz and vY = 26.8 1012 Hz, respectively. The respective force constants are KX = 325 N/m and KY = 446 N/m. The atomic masses of F, Cl and Br are 19.0, 35.5 and 79.9 atomic mass unit respectively.The halogen molecules X2 and Y2 area)X2 = F2 and Y2 = Cl2b)X2 = Cl2 and Y2 = F2c)X2 = Br2 and Y2 = F2d)X2 = F2 and Y2 = Br2Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Vibrations of diatomic molecules can be represented as those of harmonic oscillators. Two halogen molecules X2 and Y2 have fundamental vibrational frequencies vX = 16.7 1012 Hz and vY = 26.8 1012 Hz, respectively. The respective force constants are KX = 325 N/m and KY = 446 N/m. The atomic masses of F, Cl and Br are 19.0, 35.5 and 79.9 atomic mass unit respectively.The halogen molecules X2 and Y2 area)X2 = F2 and Y2 = Cl2b)X2 = Cl2 and Y2 = F2c)X2 = Br2 and Y2 = F2d)X2 = F2 and Y2 = Br2Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Vibrations of diatomic molecules can be represented as those of harmonic oscillators. Two halogen molecules X2 and Y2 have fundamental vibrational frequencies vX = 16.7 1012 Hz and vY = 26.8 1012 Hz, respectively. The respective force constants are KX = 325 N/m and KY = 446 N/m. The atomic masses of F, Cl and Br are 19.0, 35.5 and 79.9 atomic mass unit respectively.The halogen molecules X2 and Y2 area)X2 = F2 and Y2 = Cl2b)X2 = Cl2 and Y2 = F2c)X2 = Br2 and Y2 = F2d)X2 = F2 and Y2 = Br2Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Vibrations of diatomic molecules can be represented as those of harmonic oscillators. Two halogen molecules X2 and Y2 have fundamental vibrational frequencies vX = 16.7 1012 Hz and vY = 26.8 1012 Hz, respectively. The respective force constants are KX = 325 N/m and KY = 446 N/m. The atomic masses of F, Cl and Br are 19.0, 35.5 and 79.9 atomic mass unit respectively.The halogen molecules X2 and Y2 area)X2 = F2 and Y2 = Cl2b)X2 = Cl2 and Y2 = F2c)X2 = Br2 and Y2 = F2d)X2 = F2 and Y2 = Br2Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Vibrations of diatomic molecules can be represented as those of harmonic oscillators. Two halogen molecules X2 and Y2 have fundamental vibrational frequencies vX = 16.7 1012 Hz and vY = 26.8 1012 Hz, respectively. The respective force constants are KX = 325 N/m and KY = 446 N/m. The atomic masses of F, Cl and Br are 19.0, 35.5 and 79.9 atomic mass unit respectively.The halogen molecules X2 and Y2 area)X2 = F2 and Y2 = Cl2b)X2 = Cl2 and Y2 = F2c)X2 = Br2 and Y2 = F2d)X2 = F2 and Y2 = Br2Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice IIT JAM tests.
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