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For H2 molecule, the fundamental vibrational frequency can be taken as 4400 cm-1. The zeropoint energy of the molecule is ______ kJ mol-1 (rounded up to two decimal places).[h = 6.6×10-34 J s, c = 3×108 m s-1,NA= 6×1023 mol-1]Correct answer is between '25.80,26.40'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared
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the IIT JAM exam syllabus. Information about For H2 molecule, the fundamental vibrational frequency can be taken as 4400 cm-1. The zeropoint energy of the molecule is ______ kJ mol-1 (rounded up to two decimal places).[h = 6.6×10-34 J s, c = 3×108 m s-1,NA= 6×1023 mol-1]Correct answer is between '25.80,26.40'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam.
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For H2 molecule, the fundamental vibrational frequency can be taken as 4400 cm-1. The zeropoint energy of the molecule is ______ kJ mol-1 (rounded up to two decimal places).[h = 6.6×10-34 J s, c = 3×108 m s-1,NA= 6×1023 mol-1]Correct answer is between '25.80,26.40'. Can you explain this answer?, a detailed solution for For H2 molecule, the fundamental vibrational frequency can be taken as 4400 cm-1. The zeropoint energy of the molecule is ______ kJ mol-1 (rounded up to two decimal places).[h = 6.6×10-34 J s, c = 3×108 m s-1,NA= 6×1023 mol-1]Correct answer is between '25.80,26.40'. Can you explain this answer? has been provided alongside types of For H2 molecule, the fundamental vibrational frequency can be taken as 4400 cm-1. The zeropoint energy of the molecule is ______ kJ mol-1 (rounded up to two decimal places).[h = 6.6×10-34 J s, c = 3×108 m s-1,NA= 6×1023 mol-1]Correct answer is between '25.80,26.40'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice For H2 molecule, the fundamental vibrational frequency can be taken as 4400 cm-1. The zeropoint energy of the molecule is ______ kJ mol-1 (rounded up to two decimal places).[h = 6.6×10-34 J s, c = 3×108 m s-1,NA= 6×1023 mol-1]Correct answer is between '25.80,26.40'. Can you explain this answer? tests, examples and also practice IIT JAM tests.