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For H2 molecule, the fundamental vibrational frequency  can be taken as 4400 cm-1. The zeropoint energy of the molecule is ______ kJ mol-1 (rounded up to two decimal places).
[h = 6.6×10-34 J s, c = 3×108 m s-1,NA = 6×1023 mol-1]
    Correct answer is between '25.80,26.40'. Can you explain this answer?
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    For H2 molecule, the fundamental vibrational frequency can be taken as...
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    For H2 molecule, the fundamental vibrational frequency can be taken as...
    26.136kj/mol
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    For H2 molecule, the fundamental vibrational frequency can be taken as 4400 cm-1. The zeropoint energy of the molecule is ______ kJ mol-1 (rounded up to two decimal places).[h = 6.6×10-34 J s, c = 3×108 m s-1,NA= 6×1023 mol-1]Correct answer is between '25.80,26.40'. Can you explain this answer?
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    For H2 molecule, the fundamental vibrational frequency can be taken as 4400 cm-1. The zeropoint energy of the molecule is ______ kJ mol-1 (rounded up to two decimal places).[h = 6.6×10-34 J s, c = 3×108 m s-1,NA= 6×1023 mol-1]Correct answer is between '25.80,26.40'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about For H2 molecule, the fundamental vibrational frequency can be taken as 4400 cm-1. The zeropoint energy of the molecule is ______ kJ mol-1 (rounded up to two decimal places).[h = 6.6×10-34 J s, c = 3×108 m s-1,NA= 6×1023 mol-1]Correct answer is between '25.80,26.40'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For H2 molecule, the fundamental vibrational frequency can be taken as 4400 cm-1. The zeropoint energy of the molecule is ______ kJ mol-1 (rounded up to two decimal places).[h = 6.6×10-34 J s, c = 3×108 m s-1,NA= 6×1023 mol-1]Correct answer is between '25.80,26.40'. Can you explain this answer?.
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