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The compound obtained by the reaction of ethene with diborane followed by hydrolysis with alkaline hydrogen peroxide is
  • a)
    Ethanol
  • b)
    Ethanal
  • c)
    Propanol
  • d)
    Triethyl boride
Correct answer is option 'A'. Can you explain this answer?
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The compound obtained by the reaction of ethene with diborane followed...
The hydroboration oxidation reaction is a reaction that converts an alkene into neutral alcohol by the net addition of water across the double bond.

The hydrogen and hydroxyl groups are added in a syn addition leading to cis stereochemistry. Hydroboration oxidation is an anti-markovnikov reaction, with the hydroxyl group attaching to the less-substituted carbon. In the hydroboration - oxidation reaction of propene the organic compound formed is Ethanol.
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The compound obtained by the reaction of ethene with diborane followed...
Reaction and Mechanism:

The reaction of ethene with diborane (B2H6) followed by hydrolysis with alkaline hydrogen peroxide (H2O2) results in the formation of ethanol.

1. Addition of Ethene with Diborane:

The addition of ethene with diborane takes place in a concerted manner, forming an unstable intermediate.

C2H4 + B2H6 → C2H6B2

2. Hydrolysis of Ethyl Borane:

The ethyl borane formed in the previous step is hydrolyzed with alkaline hydrogen peroxide to form ethanol.

C2H6B2 + H2O2 + NaOH → 2NaBO2 + 3H2O + C2H5OH

Final Product:

The final product obtained is ethanol.

Ethene + Diborane → Ethyl Borane
Ethyl Borane + Alkaline Hydrogen Peroxide → Ethanol

Therefore, option A is the correct answer.
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Consider a solution of CH3COONH4 which is a salt of weak acid weak base. Theequilibrium involved in the solutions are :If we add these three reactions, then the net reaction isBoth CH3C00- and NH4 get hydrolysed independently and their hydrolysis depends on(i) their initial concentration(ii) the value of Kh which is Since both of the ions were produced from the same salt, their initial concentrations are same . Therefore unless untial the value of Kw/Kaand Kb is same, the degree of hydrolysis of ion cant be same.To explain why we assume that degree of hydrolysis of cation and anion is same, we need to now look at the third reaction i.e., combination of H+ and OH ions. It is obvious that this reaction happens only because one reaction produced H+ ion and the other produced OH ions. We can also note that this reaction causes both the hydrolysis reaction to occur more since their product ions are being consumed. Keep this thing in mind that the equilibrium which has smaller value of equilibrium conxtant is affected more by the common ion effect. For the same reason if for any reason a reaction is made to occur to a greater extent by the consumption of any one of the product ion, the reaction with the smaller value of equilibrium constant tends to get affected more.Therefore we conclude that firstly the hydrolysis of both the ions ocurs more in the presence of each other (due to consumption of the product ions) than in each other is absence. Secondly the hydrolysis of the ion which occurs to a lesser extent (due to smaller value of Kh) is affected more than the one whose Kh is greater. Hence we can see that the degree of hydrolysis of both the ions would be close to each other when they are getting hydrolysed in the presence of each other.Q.In a solution of NaHCO3 , the amphiprotic anion can under ionization to form H+ ion and hydrolysis to from OH ion.To calculat PH, suitable approximation is

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The compound obtained by the reaction of ethene with diborane followed by hydrolysis with alkaline hydrogen peroxide isa)Ethanolb)Ethanalc)Propanold)Triethyl borideCorrect answer is option 'A'. Can you explain this answer?
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