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Given thatT=298KNow on the basis of above data which of the following predictions will be most appropriate under the standard conditions and reversible reaction.a)Finely divided form of CuO kept in excess O2 would be completely converted to Cu2O.b)Finely divided form of Cu2O kept in excess O2 would be completely converted to CuO.c)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of CuO).d)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of Cu2O).Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Given thatT=298KNow on the basis of above data which of the following predictions will be most appropriate under the standard conditions and reversible reaction.a)Finely divided form of CuO kept in excess O2 would be completely converted to Cu2O.b)Finely divided form of Cu2O kept in excess O2 would be completely converted to CuO.c)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of CuO).d)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of Cu2O).Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given thatT=298KNow on the basis of above data which of the following predictions will be most appropriate under the standard conditions and reversible reaction.a)Finely divided form of CuO kept in excess O2 would be completely converted to Cu2O.b)Finely divided form of Cu2O kept in excess O2 would be completely converted to CuO.c)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of CuO).d)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of Cu2O).Correct answer is option 'B'. Can you explain this answer?.

Solutions for Given thatT=298KNow on the basis of above data which of the following predictions will be most appropriate under the standard conditions and reversible reaction.a)Finely divided form of CuO kept in excess O2 would be completely converted to Cu2O.b)Finely divided form of Cu2O kept in excess O2 would be completely converted to CuO.c)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of CuO).d)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of Cu2O).Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Given thatT=298KNow on the basis of above data which of the following predictions will be most appropriate under the standard conditions and reversible reaction.a)Finely divided form of CuO kept in excess O2 would be completely converted to Cu2O.b)Finely divided form of Cu2O kept in excess O2 would be completely converted to CuO.c)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of CuO).d)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of Cu2O).Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Given thatT=298KNow on the basis of above data which of the following predictions will be most appropriate under the standard conditions and reversible reaction.a)Finely divided form of CuO kept in excess O2 would be completely converted to Cu2O.b)Finely divided form of Cu2O kept in excess O2 would be completely converted to CuO.c)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of CuO).d)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of Cu2O).Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Given thatT=298KNow on the basis of above data which of the following predictions will be most appropriate under the standard conditions and reversible reaction.a)Finely divided form of CuO kept in excess O2 would be completely converted to Cu2O.b)Finely divided form of Cu2O kept in excess O2 would be completely converted to CuO.c)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of CuO).d)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of Cu2O).Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Given thatT=298KNow on the basis of above data which of the following predictions will be most appropriate under the standard conditions and reversible reaction.a)Finely divided form of CuO kept in excess O2 would be completely converted to Cu2O.b)Finely divided form of Cu2O kept in excess O2 would be completely converted to CuO.c)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of CuO).d)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of Cu2O).Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Given thatT=298KNow on the basis of above data which of the following predictions will be most appropriate under the standard conditions and reversible reaction.a)Finely divided form of CuO kept in excess O2 would be completely converted to Cu2O.b)Finely divided form of Cu2O kept in excess O2 would be completely converted to CuO.c)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of CuO).d)Finely divided form of CuO kept in excess O2 would be converted to a mixture of CuO and Cu2O (having more of Cu2O).Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.