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The transition Reynolds number for flow over a flat plate is 5 x 105. What is the distance from the leading edge at which transition will occur for flow of water with a uniform velocity of 1 m/s (for water the kinematic viscosity v = 0.86 x 10-6m2/s)
  • a)
    0.43 m
  • b)
    1 m
  • c)
    43 m
  • d)
    103 m
Correct answer is option 'A'. Can you explain this answer?
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The transition Reynolds number for flow over a flat plate is 5 x 105. ...
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The transition Reynolds number for flow over a flat plate is 5 x 105. ...
Given data:
Transition Reynolds number (Re) = 5 x 10^5
Velocity of water (V) = 1 m/s
Kinematic viscosity of water (v) = 0.86 x 10^-6 m^2/s

We need to find the distance from the leading edge at which transition will occur.

Explanation:
1. Reynolds number (Re) is a dimensionless quantity that describes the ratio of inertial forces to viscous forces in a fluid. It is given by the formula:
Re = ρVD/ν, where ρ is the density of the fluid, V is the velocity of the fluid, D is the characteristic length (in this case, the distance from the leading edge), and ν is the kinematic viscosity of the fluid.

2. The transition Reynolds number is the value of Reynolds number at which laminar flow changes to turbulent flow. For flow over a flat plate, the transition Reynolds number is approximately 5 x 10^5.

3. To find the distance from the leading edge at which transition will occur, we can rearrange the formula for Reynolds number as:
D = Reν/Vρ

4. Substituting the given values, we get:
D = (5 x 10^5) x (0.86 x 10^-6) / (1 x 1000) = 0.43 m

5. Therefore, the distance from the leading edge at which transition will occur for flow of water with a uniform velocity of 1 m/s is 0.43 m.

Final Answer: The correct option is (A) 0.43 m.
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