IIT JAM Exam > IIT JAM Questions > Bar magnet of magnetic moment 200 A-m2is susp...
Start Learning for Free
Bar magnet of magnetic moment 200 A-m2 is suspended in a magnetic field of intensity 0.25N/Am. The couple required to deflect it through 30° is
- a)15 N-m
- b)20N-m
- c)25 N-m
- d)50 N-m
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
Bar magnet of magnetic moment 200 A-m2is suspended in a magnetic field...
The torque experienced by a bar magnet in a magnetic field is given by the equation:
τ = mBsinθ
Where:
τ = torque (Nm)
m = magnetic moment of the bar magnet (A-m²)
B = magnetic field intensity (T)
θ = angle between the magnetic moment and the magnetic field (radians)
In this case, the magnetic moment of the bar magnet is given as 200 A-m² and the magnetic field intensity is given as 0.25 N/Am.
To find the torque required to deflect the bar magnet through 30°, we need to calculate the angle θ in radians:
θ = 30° × (π/180°) = 0.5236 radians
Now we can calculate the torque:
τ = (200 A-m²) × (0.25 N/Am) × sin(0.5236 radians)
= 25 Nm
Therefore, the couple required to deflect the bar magnet through 30° is 25 Nm.
τ = mBsinθ
Where:
τ = torque (Nm)
m = magnetic moment of the bar magnet (A-m²)
B = magnetic field intensity (T)
θ = angle between the magnetic moment and the magnetic field (radians)
In this case, the magnetic moment of the bar magnet is given as 200 A-m² and the magnetic field intensity is given as 0.25 N/Am.
To find the torque required to deflect the bar magnet through 30°, we need to calculate the angle θ in radians:
θ = 30° × (π/180°) = 0.5236 radians
Now we can calculate the torque:
τ = (200 A-m²) × (0.25 N/Am) × sin(0.5236 radians)
= 25 Nm
Therefore, the couple required to deflect the bar magnet through 30° is 25 Nm.
|
Explore Courses for IIT JAM exam
|
|
Similar IIT JAM Doubts
Bar magnet of magnetic moment 200 A-m2is suspended in a magnetic field of intensity 0.25N/Am. The couple required to deflect it through 30° isa)15 N-mb)20N-mc)25 N-md)50 N-mCorrect answer is option 'B'. Can you explain this answer?
Question Description
Bar magnet of magnetic moment 200 A-m2is suspended in a magnetic field of intensity 0.25N/Am. The couple required to deflect it through 30° isa)15 N-mb)20N-mc)25 N-md)50 N-mCorrect answer is option 'B'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Bar magnet of magnetic moment 200 A-m2is suspended in a magnetic field of intensity 0.25N/Am. The couple required to deflect it through 30° isa)15 N-mb)20N-mc)25 N-md)50 N-mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Bar magnet of magnetic moment 200 A-m2is suspended in a magnetic field of intensity 0.25N/Am. The couple required to deflect it through 30° isa)15 N-mb)20N-mc)25 N-md)50 N-mCorrect answer is option 'B'. Can you explain this answer?.
Bar magnet of magnetic moment 200 A-m2is suspended in a magnetic field of intensity 0.25N/Am. The couple required to deflect it through 30° isa)15 N-mb)20N-mc)25 N-md)50 N-mCorrect answer is option 'B'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Bar magnet of magnetic moment 200 A-m2is suspended in a magnetic field of intensity 0.25N/Am. The couple required to deflect it through 30° isa)15 N-mb)20N-mc)25 N-md)50 N-mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Bar magnet of magnetic moment 200 A-m2is suspended in a magnetic field of intensity 0.25N/Am. The couple required to deflect it through 30° isa)15 N-mb)20N-mc)25 N-md)50 N-mCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Bar magnet of magnetic moment 200 A-m2is suspended in a magnetic field of intensity 0.25N/Am. The couple required to deflect it through 30° isa)15 N-mb)20N-mc)25 N-md)50 N-mCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for IIT JAM.
Download more important topics, notes, lectures and mock test series for IIT JAM Exam by signing up for free.
Here you can find the meaning of Bar magnet of magnetic moment 200 A-m2is suspended in a magnetic field of intensity 0.25N/Am. The couple required to deflect it through 30° isa)15 N-mb)20N-mc)25 N-md)50 N-mCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Bar magnet of magnetic moment 200 A-m2is suspended in a magnetic field of intensity 0.25N/Am. The couple required to deflect it through 30° isa)15 N-mb)20N-mc)25 N-md)50 N-mCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Bar magnet of magnetic moment 200 A-m2is suspended in a magnetic field of intensity 0.25N/Am. The couple required to deflect it through 30° isa)15 N-mb)20N-mc)25 N-md)50 N-mCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Bar magnet of magnetic moment 200 A-m2is suspended in a magnetic field of intensity 0.25N/Am. The couple required to deflect it through 30° isa)15 N-mb)20N-mc)25 N-md)50 N-mCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Bar magnet of magnetic moment 200 A-m2is suspended in a magnetic field of intensity 0.25N/Am. The couple required to deflect it through 30° isa)15 N-mb)20N-mc)25 N-md)50 N-mCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice IIT JAM tests.
|
|
Explore Courses for IIT JAM exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup