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Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.
(Specify your answer to two digits after the decimal point.)
Correct answer is '3000'. Can you explain this answer?
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Most Upvoted Answer
Consider a Carnot engine operating between temperatures of 600K and 40...
Efficiency (Η)=1-T2/T1=W/Q1
1-400/600=1000/Q1
1/3=1000/Q1
Q1=3000j
(Q1=heat extracted )
1-400/600=1000/Q1
1/3=1000/Q1
Q1=3000j
(Q1=heat extracted )
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Consider a Carnot engine operating between temperatures of 600K and 40...
Given data:
- High temperature (hot) reservoir temperature (Th) = 600K
- Low temperature (cold) reservoir temperature (Tc) = 400K
- Work performed per cycle (W) = 1000 J
Explanation:
A Carnot engine is an idealized heat engine that operates between two heat reservoirs and achieves maximum efficiency. The efficiency of a Carnot engine is given by the formula:
η = 1 - (Tc/Th)
where η is the efficiency, Tc is the temperature of the cold reservoir, and Th is the temperature of the hot reservoir.
Step 1: Calculating the efficiency of the Carnot engine
In this case, we can calculate the efficiency using the given temperatures:
η = 1 - (400/600) = 1 - (2/3) = 1/3
Step 2: Calculating the heat extracted from the hot reservoir
The heat extracted from the hot reservoir (Qh) can be calculated using the formula:
Qh = W/η
where Qh is the heat extracted from the hot reservoir and W is the work performed per cycle.
Qh = 1000 / (1/3) = 3000 J
Therefore, the heat extracted per cycle from the high-temperature reservoir is 3000 J.
- High temperature (hot) reservoir temperature (Th) = 600K
- Low temperature (cold) reservoir temperature (Tc) = 400K
- Work performed per cycle (W) = 1000 J
Explanation:
A Carnot engine is an idealized heat engine that operates between two heat reservoirs and achieves maximum efficiency. The efficiency of a Carnot engine is given by the formula:
η = 1 - (Tc/Th)
where η is the efficiency, Tc is the temperature of the cold reservoir, and Th is the temperature of the hot reservoir.
Step 1: Calculating the efficiency of the Carnot engine
In this case, we can calculate the efficiency using the given temperatures:
η = 1 - (400/600) = 1 - (2/3) = 1/3
Step 2: Calculating the heat extracted from the hot reservoir
The heat extracted from the hot reservoir (Qh) can be calculated using the formula:
Qh = W/η
where Qh is the heat extracted from the hot reservoir and W is the work performed per cycle.
Qh = 1000 / (1/3) = 3000 J
Therefore, the heat extracted per cycle from the high-temperature reservoir is 3000 J.
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Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer?
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Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer?.
Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer?.
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