IIT JAM Exam > IIT JAM Questions > Consider a Carnot engine operating between te...
Start Learning for Free
Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.
(Specify your answer to two digits after the decimal point.)
Correct answer is '3000'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
Consider a Carnot engine operating between temperatures of 600K and 40...
Given data:
- High temperature (hot) reservoir temperature (Th) = 600K
- Low temperature (cold) reservoir temperature (Tc) = 400K
- Work performed per cycle (W) = 1000 J
Explanation:
A Carnot engine is an idealized heat engine that operates between two heat reservoirs and achieves maximum efficiency. The efficiency of a Carnot engine is given by the formula:
η = 1 - (Tc/Th)
where η is the efficiency, Tc is the temperature of the cold reservoir, and Th is the temperature of the hot reservoir.
Step 1: Calculating the efficiency of the Carnot engine
In this case, we can calculate the efficiency using the given temperatures:
η = 1 - (400/600) = 1 - (2/3) = 1/3
Step 2: Calculating the heat extracted from the hot reservoir
The heat extracted from the hot reservoir (Qh) can be calculated using the formula:
Qh = W/η
where Qh is the heat extracted from the hot reservoir and W is the work performed per cycle.
Qh = 1000 / (1/3) = 3000 J
Therefore, the heat extracted per cycle from the high-temperature reservoir is 3000 J.
- High temperature (hot) reservoir temperature (Th) = 600K
- Low temperature (cold) reservoir temperature (Tc) = 400K
- Work performed per cycle (W) = 1000 J
Explanation:
A Carnot engine is an idealized heat engine that operates between two heat reservoirs and achieves maximum efficiency. The efficiency of a Carnot engine is given by the formula:
η = 1 - (Tc/Th)
where η is the efficiency, Tc is the temperature of the cold reservoir, and Th is the temperature of the hot reservoir.
Step 1: Calculating the efficiency of the Carnot engine
In this case, we can calculate the efficiency using the given temperatures:
η = 1 - (400/600) = 1 - (2/3) = 1/3
Step 2: Calculating the heat extracted from the hot reservoir
The heat extracted from the hot reservoir (Qh) can be calculated using the formula:
Qh = W/η
where Qh is the heat extracted from the hot reservoir and W is the work performed per cycle.
Qh = 1000 / (1/3) = 3000 J
Therefore, the heat extracted per cycle from the high-temperature reservoir is 3000 J.
Free Test
FREE
| Start Free Test |
Community Answer
Consider a Carnot engine operating between temperatures of 600K and 40...
Efficiency (Η)=1-T2/T1=W/Q1
1-400/600=1000/Q1
1/3=1000/Q1
Q1=3000j
(Q1=heat extracted )
1-400/600=1000/Q1
1/3=1000/Q1
Q1=3000j
(Q1=heat extracted )
|
Explore Courses for IIT JAM exam
|
|
Similar IIT JAM Doubts
Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer?
Question Description
Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer?.
Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer?.
Solutions for Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer? in English & in Hindi are available as part of our courses for IIT JAM.
Download more important topics, notes, lectures and mock test series for IIT JAM Exam by signing up for free.
Here you can find the meaning of Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer?, a detailed solution for Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer? has been provided alongside types of Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider a Carnot engine operating between temperatures of 600K and 400K. The engine performs 1000 J of work per cycle. The heat (in Joules) extracted per cycle from the high temperature reservoir is __________.(Specify your answer to two digits after the decimal point.)Correct answer is '3000'. Can you explain this answer? tests, examples and also practice IIT JAM tests.
|
|
Explore Courses for IIT JAM exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup