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A solid metallic cube of heat capacity S is at temperature 300K . It is brought in contact with a reservoir at 600K. If the heat transfer takes place only between the reservoir and cube, entropy change after reaching the thermal equilibrium is?
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A solid metallic cube of heat capacity S is at temperature 300K . It i...
Understanding the System
When a solid metallic cube with heat capacity S at 300K is placed in contact with a reservoir at 600K, heat transfer occurs from the reservoir to the cube until thermal equilibrium is achieved.
Heat Transfer
- The heat absorbed by the cube can be calculated using the formula:
- Q = S * (Tf - Ti)
- Where Tf is the final temperature and Ti is the initial temperature.
- In this case, Tf will be 600K (the temperature of the reservoir), and Ti is 300K.
Calculating Heat Absorbed by the Cube
- Therefore, the heat absorbed by the cube is:
- Q = S * (600K - 300K) = S * 300K
Entropy Change of the Cube
- The entropy change (ΔS_cube) of the cube can be calculated using the formula:
- ΔS_cube = Q / T_avg
- T_avg is the average temperature during the heating process.
- For the cube, the average temperature can be approximated as:
- T_avg = (Ti + Tf) / 2 = (300K + 600K) / 2 = 450K
- Thus,
- ΔS_cube = (S * 300K) / 450K = (2/3)S
Entropy Change of the Reservoir
- The entropy change (ΔS_reservoir) for the reservoir is:
- ΔS_reservoir = -Q / T_reservoir
- = - (S * 300K) / 600K = - (1/2)S
Total Entropy Change
- The total entropy change (ΔS_total) of the system is:
- ΔS_total = ΔS_cube + ΔS_reservoir
- = (2/3)S - (1/2)S
- = (1/6)S
In conclusion, the total entropy change after the system reaches thermal equilibrium is (1/6)S.
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A solid metallic cube of heat capacity S is at temperature 300K . It is brought in contact with a reservoir at 600K. If the heat transfer takes place only between the reservoir and cube, entropy change after reaching the thermal equilibrium is?
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