A smooth pipe of diameter 200 mm carries water. The pressure in the pi...

Applying Bernoulli’s equation between section S
1 and S
2
as area is constant velocity head will be same

thus flow from S
1 to S
2 and head loss is 1.06 m.
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A smooth pipe of diameter 200 mm carries water. The pressure in the pi...
Given information:
- Diameter of the pipe = 200 mm
- Pressure at section S1 (elevation: 10 m) = 50 kPa
- Pressure at section S2 (elevation: 12 m) = 20 kPa
- Velocity at section S2 = 2 m/s
- Density of water = 1000 kg/m^3
- Acceleration due to gravity = 9.8 m/s^2
Analysis:
To determine the flow direction and head loss, we can use Bernoulli's equation. Bernoulli's equation states that the total energy of a fluid is conserved along a streamline. It can be expressed as:
P1/ρ + V1^2/2 + g*z1 = P2/ρ + V2^2/2 + g*z2
Where:
P1 and P2 are the pressures at sections S1 and S2 respectively,
ρ is the density of water,
V1 and V2 are the velocities at sections S1 and S2 respectively,
g is the acceleration due to gravity,
z1 and z2 are the elevations at sections S1 and S2 respectively.
Calculation:
1. Convert the diameter of the pipe to meters:
Diameter = 200 mm = 0.2 m
2. Calculate the cross-sectional area of the pipe:
A = π*(Diameter/2)^2 = π*(0.1^2) = 0.0314 m^2
3. Calculate the velocity at section S1 using the continuity equation:
A1*V1 = A2*V2
0.0314*V1 = 0.0314*2
V1 = 2 m/s
4. Substitute the given values into Bernoulli's equation for sections S1 and S2:
50,000/1000 + 2^2/2 + 9.8*10 = 20,000/1000 + 2^2/2 + 9.8*12
5. Simplify the equation:
50 + 2^2/2 + 98 = 20 + 2^2/2 + 9.8*12
6. Solve for the head loss (Δz = z2 - z1):
Δz = 12 - 10 = 2 m
7. The correct answer is option 'C':
- Flow is from S1 to S2 (the pressure decreases from 50 kPa to 20 kPa).
- The head loss is 2 m.
Conclusion:
The flow is from section S1 to section S2 and the head loss is 2 m. Therefore, option 'C' is the correct answer.