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Answer the following questions with respect to the compound NO[BF4].
    (P) Bond order of the part underlined.
    (Q) Total number of σ bonds in the compound.
    (R) Total number of π bonds in the compound.
    (S) Number of hybrid orbitals involved in the hybridisation of boron.    
    Correct answer is '3524'. Can you explain this answer?
    Verified Answer
    Answer the following questions with respect to the compound NO[BF4]. (...
    NO+[BF4]-
    (P) Molecular orbital electronic configuration ;
    NO+ is derivative of O2, so MOT configuration is :
    σ1s2 σ*1s2 σ2s2 σ*2s2 σ2px2py2 = π2pz2
     (x is taken as molecular axis)
    Bond order = = 3
    One σ bond and two π bonds.
    (Q) Number of σ bonds in NO+ is one and in BF4- are four. So total number of σ bonds are five. 
    (R) Number of σ bonds in NO+ are two.
    (S) 
    Steric number of central atom boron is 4 + 0 = 4 ; so its hybridisation is sp3 and thus the number of hybrid orbitals
    involved in sp3 hybridisation is four.
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    Answer the following questions with respect to the compound NO[BF4]. (P) Bond order of the part underlined. (Q) Total number of σ bonds in the compound. (R) Total number of π bonds in the compound. (S) Number of hybrid orbitals involved in the hybridisation of boron. Correct answer is '3524'. Can you explain this answer?
    Question Description
    Answer the following questions with respect to the compound NO[BF4]. (P) Bond order of the part underlined. (Q) Total number of σ bonds in the compound. (R) Total number of π bonds in the compound. (S) Number of hybrid orbitals involved in the hybridisation of boron. Correct answer is '3524'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Answer the following questions with respect to the compound NO[BF4]. (P) Bond order of the part underlined. (Q) Total number of σ bonds in the compound. (R) Total number of π bonds in the compound. (S) Number of hybrid orbitals involved in the hybridisation of boron. Correct answer is '3524'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Answer the following questions with respect to the compound NO[BF4]. (P) Bond order of the part underlined. (Q) Total number of σ bonds in the compound. (R) Total number of π bonds in the compound. (S) Number of hybrid orbitals involved in the hybridisation of boron. Correct answer is '3524'. Can you explain this answer?.
    Solutions for Answer the following questions with respect to the compound NO[BF4]. (P) Bond order of the part underlined. (Q) Total number of σ bonds in the compound. (R) Total number of π bonds in the compound. (S) Number of hybrid orbitals involved in the hybridisation of boron. Correct answer is '3524'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
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