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The number of integers x such that 0.25 < 2x < 200, and 2x + 2 is perfectly divisible by either 3 or 4, is
[2018]
- a)5
- b)4
- c)3
- d)2
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The number of integers x such that 0.25 < 2x < 200, and 2x + 2 i...
0.25 < 2x < 200
Possible values of x satisfying the above inequality are –2, –1, 0, 1, 2, 3, 4, 5, 6, 7. When x = 0, 1, 2, 4 and 6, 2x + 2 is divisible by 3 or 4.
Hence, required number of values of x is 5.
Possible values of x satisfying the above inequality are –2, –1, 0, 1, 2, 3, 4, 5, 6, 7. When x = 0, 1, 2, 4 and 6, 2x + 2 is divisible by 3 or 4.
Hence, required number of values of x is 5.
Most Upvoted Answer
The number of integers x such that 0.25 < 2x < 200, and 2x + 2 i...
To find the number of integers x that satisfy the inequality 0.25 < x="" />< 10.75,="" we="" need="" to="" find="" the="" number="" of="" integers="" between="" 1="" and="" 10.="" />
There are 10 integers between 1 and 10, inclusive. Therefore, the number of integers x that satisfy the inequality is 10.
There are 10 integers between 1 and 10, inclusive. Therefore, the number of integers x that satisfy the inequality is 10.
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