Solution:

Given, 2x+3y+4=0 and v(x)=6

To find: v(y)

We know that, v(kp) = |k| * v(p), where k is a constant and p is a variable.

Let's use this formula to find v(y).

First, we need to isolate y in the given equation.

2x + 3y + 4 = 0

3y = -2x - 4

y = (-2/3)x - 4/3

Now, we can use the formula for v(y):

v(y) = |(-2/3)| * v(x) (since y = (-2/3)x - 4/3)

v(y) = (2/3) * 6

v(y) = 4

Therefore, v(y) is 4.

Explanation:

To solve this problem, we need to use the formula v(kp) = |k| * v(p), where k is a constant and p is a variable. This formula is used to find the absolute value of the coefficient of a variable and then multiply it by the value of the variable's corresponding coefficient.

We are given an equation 2x+3y+4=0 and we need to find v(y) when v(x)=6. To find v(y), we need to isolate y in the given equation. Once we have isolated y, we can use the formula v(kp) = |k| * v(p) to find v(y).

After isolating y, we get y = (-2/3)x - 4/3. Now, we can use the formula v(y) = |(-2/3)| * v(x) to find v(y). Since the absolute value of -2/3 is 2/3, we substitute this value in the formula along with v(x) = 6 to get v(y) = (2/3) * 6 = 4.

Therefore, v(y) is 4.