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If for two independent events A and B, p(A union B)=2/3 and p(A)=2/5 then p(B)=???
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If for two independent events A and B, p(A union B)=2/3 and p(A)=2/5 t...
Solution:


Introduction:


Let's understand the given information first:



  • p(A union B) = 2/3

  • p(A) = 2/5



We need to find p(B).


Explanation:


To solve this problem, we will use the formula for the probability of the union of two events:


p(A union B) = p(A) + p(B) - p(A intersection B)


Since A and B are independent events, p(A intersection B) = p(A) * p(B).


Now we can substitute the given values and simplify:


2/3 = 2/5 + p(B) - (2/5 * p(B))


2/3 = 2/5 + p(B) - (2/5p(B))


2/3 = 2/5 + 3p(B)/5


2/15 = 3p(B)/5


p(B) = (2/15) * (5/3) = 2/9


Conclusion:


Therefore, the probability of event B is 2/9.
Community Answer
If for two independent events A and B, p(A union B)=2/3 and p(A)=2/5 t...
condition of independent event is p(A intersection B)=p(A)*p(B)....and formula for calculating p(A union B)=p(A)+p(B)-p(A intersection B) ..... replace p(A intersection B) with its condition.so it can be written as ...... .p(A union B)=p(A)+p(B)-p(A)*p(B) and substitute the value n u get ans 4/9
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If for two independent events A and B, p(A union B)=2/3 and p(A)=2/5 then p(B)=???
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If for two independent events A and B, p(A union B)=2/3 and p(A)=2/5 then p(B)=??? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If for two independent events A and B, p(A union B)=2/3 and p(A)=2/5 then p(B)=??? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If for two independent events A and B, p(A union B)=2/3 and p(A)=2/5 then p(B)=???.
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