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A vessel of volume 1m3 contains oxygen (molecular weight = 32) at P = 1 bar and T = 47°C. The mass of oxygen in the vessel is (take universal gas constant as 8314 J/mol-K)
- a)40 kg
- b)3 kg
- c)1.2 kg
- d)1kg
Correct answer is option 'C'. Can you explain this answer?
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A vessel of volume1m3 contains oxygen (molecular weight = 32) at P = 1...
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A vessel of volume1m3 contains oxygen (molecular weight = 32) at P = 1...
To solve this problem, we need to use the ideal gas law equation:
PV = nRT
Where:
P = Pressure (in bar)
V = Volume (in m^3)
n = Number of moles
R = Ideal gas constant (0.0831 L bar / K mol)
T = Temperature (in Kelvin)
First, let's convert the given temperature from Celsius to Kelvin:
T = 47 + 273 = 320 K
Next, we can rearrange the ideal gas law equation to solve for the number of moles:
n = PV / RT
Given:
P = 1 bar
V = 1 m^3
R = 0.0831 L bar / K mol
T = 320 K
Plugging in the values:
n = (1 bar * 1 m^3) / (0.0831 L bar / K mol * 320 K)
To convert m^3 to L, we need to multiply by 1000:
n = (1 bar * 1000 L) / (0.0831 L bar / K mol * 320 K)
Simplifying the units:
n = 12038.95 mol
Therefore, the vessel contains approximately 12038.95 moles of oxygen.
PV = nRT
Where:
P = Pressure (in bar)
V = Volume (in m^3)
n = Number of moles
R = Ideal gas constant (0.0831 L bar / K mol)
T = Temperature (in Kelvin)
First, let's convert the given temperature from Celsius to Kelvin:
T = 47 + 273 = 320 K
Next, we can rearrange the ideal gas law equation to solve for the number of moles:
n = PV / RT
Given:
P = 1 bar
V = 1 m^3
R = 0.0831 L bar / K mol
T = 320 K
Plugging in the values:
n = (1 bar * 1 m^3) / (0.0831 L bar / K mol * 320 K)
To convert m^3 to L, we need to multiply by 1000:
n = (1 bar * 1000 L) / (0.0831 L bar / K mol * 320 K)
Simplifying the units:
n = 12038.95 mol
Therefore, the vessel contains approximately 12038.95 moles of oxygen.
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Question Description
A vessel of volume1m3 contains oxygen (molecular weight = 32) at P = 1 bar and T = 47°C. The mass of oxygen in the vessel is (take universal gas constant as 8314 J/mol-K)a)40 kgb)3 kgc)1.2 kgd)1kgCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A vessel of volume1m3 contains oxygen (molecular weight = 32) at P = 1 bar and T = 47°C. The mass of oxygen in the vessel is (take universal gas constant as 8314 J/mol-K)a)40 kgb)3 kgc)1.2 kgd)1kgCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A vessel of volume1m3 contains oxygen (molecular weight = 32) at P = 1 bar and T = 47°C. The mass of oxygen in the vessel is (take universal gas constant as 8314 J/mol-K)a)40 kgb)3 kgc)1.2 kgd)1kgCorrect answer is option 'C'. Can you explain this answer?.
A vessel of volume1m3 contains oxygen (molecular weight = 32) at P = 1 bar and T = 47°C. The mass of oxygen in the vessel is (take universal gas constant as 8314 J/mol-K)a)40 kgb)3 kgc)1.2 kgd)1kgCorrect answer is option 'C'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A vessel of volume1m3 contains oxygen (molecular weight = 32) at P = 1 bar and T = 47°C. The mass of oxygen in the vessel is (take universal gas constant as 8314 J/mol-K)a)40 kgb)3 kgc)1.2 kgd)1kgCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A vessel of volume1m3 contains oxygen (molecular weight = 32) at P = 1 bar and T = 47°C. The mass of oxygen in the vessel is (take universal gas constant as 8314 J/mol-K)a)40 kgb)3 kgc)1.2 kgd)1kgCorrect answer is option 'C'. Can you explain this answer?.
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