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Find the altitude of a trapezium, the sum of the lengths of whose bases is 6.5 cm and whose area is 26 cm2.
  • a)
    10 cm
  • b)
    8 cm
  • c)
    6 cm
  • d)
    12 cm
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Find the altitude of a trapezium, the sum of the lengths of whose base...
The sum of the lengths of whose base = 6.5
area of trapezium = 26cm2

area of trapezium = 1/2(a+b)*h
26cm2= 1/2(6.5)*h
h =26*2/6.5
              h =52/6.5
              h =8cm
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Community Answer
Find the altitude of a trapezium, the sum of the lengths of whose base...
Given:
Sum of the lengths of bases = 6.5 cm
Area of trapezium = 26 cm²

To find:
Altitude of trapezium

Solution:

Let's assume that the two bases of the trapezium are AB and CD, where AB is larger than CD. Let the altitude of the trapezium be 'h'.

Area of trapezium = 1/2 x (sum of bases) x (altitude)
26 = 1/2 x (6.5) x h
52 = 6.5h
h = 52/6.5
h = 8 cm

Therefore, the altitude of the trapezium is 8 cm.

Answer:
Option B, 8 cm
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