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In experiment 1.288 gram of copper oxide was obtained from 1.03 gram of of copper . In another experiment 3.672 gram of copper oxide gave on reduction 2.93 8 gram of copper. So that those figures verify the law of constant proportion.?
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In experiment 1.288 gram of copper oxide was obtained from 1.03 gram o...
Verification of Law of Constant Proportion
Experiment 1:
- 1.03 gram of copper was used.
- 1.288 gram of copper oxide was obtained.
Experiment 2:
- 3.672 gram of copper oxide was used.
- 2.938 gram of copper was obtained on reduction.
Explanation
The law of constant proportion states that the proportion by mass of the elements in a given compound is always the same. In other words, the ratio of the masses of two elements in a compound is always constant.
In the first experiment, 1.03 gram of copper combined with oxygen to form 1.288 gram of copper oxide. This means that the ratio of copper to oxygen in copper oxide is 1.03:0.258, or 4:1.
In the second experiment, 3.672 gram of copper oxide was reduced to 2.938 gram of copper. Using the ratio of copper to oxygen in copper oxide that was determined in the first experiment, we can calculate that the expected mass of copper that should be obtained is 3.672 x 4/5 = 2.938 gram. The actual mass of copper obtained in the experiment matches this expected value, confirming the law of constant proportion.
Conclusion
The results of the two experiments verify the law of constant proportion, which states that the proportion by mass of the elements in a given compound is always the same.
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In experiment 1.288 gram of copper oxide was obtained from 1.03 gram of of copper . In another experiment 3.672 gram of copper oxide gave on reduction 2.93 8 gram of copper. So that those figures verify the law of constant proportion.?
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In experiment 1.288 gram of copper oxide was obtained from 1.03 gram of of copper . In another experiment 3.672 gram of copper oxide gave on reduction 2.93 8 gram of copper. So that those figures verify the law of constant proportion.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about In experiment 1.288 gram of copper oxide was obtained from 1.03 gram of of copper . In another experiment 3.672 gram of copper oxide gave on reduction 2.93 8 gram of copper. So that those figures verify the law of constant proportion.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In experiment 1.288 gram of copper oxide was obtained from 1.03 gram of of copper . In another experiment 3.672 gram of copper oxide gave on reduction 2.93 8 gram of copper. So that those figures verify the law of constant proportion.?.
In experiment 1.288 gram of copper oxide was obtained from 1.03 gram of of copper . In another experiment 3.672 gram of copper oxide gave on reduction 2.93 8 gram of copper. So that those figures verify the law of constant proportion.? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about In experiment 1.288 gram of copper oxide was obtained from 1.03 gram of of copper . In another experiment 3.672 gram of copper oxide gave on reduction 2.93 8 gram of copper. So that those figures verify the law of constant proportion.? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In experiment 1.288 gram of copper oxide was obtained from 1.03 gram of of copper . In another experiment 3.672 gram of copper oxide gave on reduction 2.93 8 gram of copper. So that those figures verify the law of constant proportion.?.
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