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The average weekly food expenditure of a group of families has a normal distribution with mean Rs. 1,800 and standard deviation Rs. 300. What is the probability that out of 5 families belonging to this group, at least one family has weekly food expenditure in excess of Rs. 1,800? Given(1) = 0.84.a)0.418b)0.582c)0.386d)0.614Correct answer is option 'B'. Can you explain this answer? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about The average weekly food expenditure of a group of families has a normal distribution with mean Rs. 1,800 and standard deviation Rs. 300. What is the probability that out of 5 families belonging to this group, at least one family has weekly food expenditure in excess of Rs. 1,800? Given(1) = 0.84.a)0.418b)0.582c)0.386d)0.614Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The average weekly food expenditure of a group of families has a normal distribution with mean Rs. 1,800 and standard deviation Rs. 300. What is the probability that out of 5 families belonging to this group, at least one family has weekly food expenditure in excess of Rs. 1,800? Given(1) = 0.84.a)0.418b)0.582c)0.386d)0.614Correct answer is option 'B'. Can you explain this answer?.

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Here you can find the meaning of The average weekly food expenditure of a group of families has a normal distribution with mean Rs. 1,800 and standard deviation Rs. 300. What is the probability that out of 5 families belonging to this group, at least one family has weekly food expenditure in excess of Rs. 1,800? Given(1) = 0.84.a)0.418b)0.582c)0.386d)0.614Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The average weekly food expenditure of a group of families has a normal distribution with mean Rs. 1,800 and standard deviation Rs. 300. What is the probability that out of 5 families belonging to this group, at least one family has weekly food expenditure in excess of Rs. 1,800? Given(1) = 0.84.a)0.418b)0.582c)0.386d)0.614Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The average weekly food expenditure of a group of families has a normal distribution with mean Rs. 1,800 and standard deviation Rs. 300. What is the probability that out of 5 families belonging to this group, at least one family has weekly food expenditure in excess of Rs. 1,800? Given(1) = 0.84.a)0.418b)0.582c)0.386d)0.614Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The average weekly food expenditure of a group of families has a normal distribution with mean Rs. 1,800 and standard deviation Rs. 300. What is the probability that out of 5 families belonging to this group, at least one family has weekly food expenditure in excess of Rs. 1,800? Given(1) = 0.84.a)0.418b)0.582c)0.386d)0.614Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The average weekly food expenditure of a group of families has a normal distribution with mean Rs. 1,800 and standard deviation Rs. 300. What is the probability that out of 5 families belonging to this group, at least one family has weekly food expenditure in excess of Rs. 1,800? Given(1) = 0.84.a)0.418b)0.582c)0.386d)0.614Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice CA Foundation tests.