JEE Exam  >  JEE Questions  >  Find the extremum value of √x² y² when 13x² -... Start Learning for Free
Find the extremum value of √x² y² when 13x² - 10xy 13y² = 72?
Most Upvoted Answer
Find the extremum value of √x² y² when 13x² - 10xy 13y² = 72?
**Solution:**

To find the extremum value of √(x²y²) subject to the constraint 13x² - 10xy + 13y² = 72, we will use the method of Lagrange multipliers.

**Step 1: Formulating the Problem**

We start by defining the function f(x, y) = √(x²y²), which represents the quantity we want to optimize. We also have the constraint function g(x, y) = 13x² - 10xy + 13y² = 72.

**Step 2: Setting up the Lagrange Multiplier Equation**

We introduce a Lagrange multiplier λ and set up the Lagrange multiplier equation:

∇f = λ∇g

where ∇f and ∇g are the gradients of f and g, respectively.

The gradient of f is given by:

∇f = (∂f/∂x, ∂f/∂y) = (2xy²/√(x²y²), 2x²y/√(x²y²))

The gradient of g is given by:

∇g = (∂g/∂x, ∂g/∂y) = (26x - 10y, 26y - 10x)

**Step 3: Solving the Lagrange Multiplier Equation**

By equating the components of the gradients and multiplying by √(x²y²), we get the following system of equations:

2xy² = λ(26x - 10y)
2x²y = λ(26y - 10x)
13x² - 10xy + 13y² = 72

Simplifying the first two equations, we have:

13xy² - 5xyy = 13λx² - 5λxy
13x²y - 5xyx = 13λy² - 5λxy

Combining like terms, we get:

13xy² - 5xyy - 13λx² + 5λxy = 0
13x²y - 5xyx - 13λy² + 5λxy = 0

Factoring out common terms, we obtain:

xy(13x - 5y - 13λx + 5λ) = 0
xy(13y - 5x - 13λy + 5λ) = 0

Since xy cannot be zero, we have two possibilities:

1. 13x - 5y - 13λx + 5λ = 0
2. 13y - 5x - 13λy + 5λ = 0

**Step 4: Solving the System of Equations**

We solve the system of equations to find the values of x, y, and λ that satisfy the conditions. Adding and subtracting the two equations, we get:

(13 - 13λ)x + (5λ - 5)y = 0
(13 - 13λ)y + (5λ - 5)x = 0

Simplifying, we have:

(13 - 13λ)(x - y) = 0
(13 - 13λ)(y - x) = 0

This
Community Answer
Find the extremum value of √x² y² when 13x² - 10xy 13y² = 72?
55
Explore Courses for JEE exam
Find the extremum value of √x² y² when 13x² - 10xy 13y² = 72?
Question Description
Find the extremum value of √x² y² when 13x² - 10xy 13y² = 72? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Find the extremum value of √x² y² when 13x² - 10xy 13y² = 72? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the extremum value of √x² y² when 13x² - 10xy 13y² = 72?.
Solutions for Find the extremum value of √x² y² when 13x² - 10xy 13y² = 72? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Find the extremum value of √x² y² when 13x² - 10xy 13y² = 72? defined & explained in the simplest way possible. Besides giving the explanation of Find the extremum value of √x² y² when 13x² - 10xy 13y² = 72?, a detailed solution for Find the extremum value of √x² y² when 13x² - 10xy 13y² = 72? has been provided alongside types of Find the extremum value of √x² y² when 13x² - 10xy 13y² = 72? theory, EduRev gives you an ample number of questions to practice Find the extremum value of √x² y² when 13x² - 10xy 13y² = 72? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev