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 be such that A has real eigenvalues then
  • a)
    θ = nπ for some integer n
  • b)
     for some integer n
  • c)
    there is no restriction on θ
  • d)
    for some integer n
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
be such that A has real eigenvalues thena)θ = nπ for some int...
Eigen value are real in this case , that's why option c is right
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