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The number of solutions for the eqn sin (e^x)= 5^x +5^-x is 0, 1, 2, infinitely many: CAN ANY ONE SOLVE THIS PLZZ. .
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The number of solutions for the eqn sin (e^x)= 5^x +5^-x is 0, 1, 2, i...
0 Because f(x)+1/f(x)>or=2 But sin is never greater than 1 So there is no solution for x
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The number of solutions for the eqn sin (e^x)= 5^x +5^-x is 0, 1, 2, i...
simply draw the graphs sin(e^x) as a normal sin graph and 5^x+5^-x you will get no intersection
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The number of solutions for the eqn sin (e^x)= 5^x +5^-x is 0, 1, 2, infinitely many: CAN ANY ONE SOLVE THIS PLZZ. .
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