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A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500∘Cand then placed on large ice block. The maximum amount (in kg) of ice that can melt is (Specific heat of copper =0.39Jg-1∘C-1, latent heat of fusion of water=335Jg-1)
Correct answer is '1.46'. Can you explain this answer?
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A copper block of mass 2.5 kg is heated in a furnace to a temperature ...
Given:
Mass of copper block = 2.5 kg
Temperature of copper block = 500°C
Specific heat of copper = 0.39 J/g°C
Latent heat of fusion of water = 335 J/g
To find:
Maximum amount of ice that can melt in kg
Assumptions:
1. The heat transfer between the copper block and the ice block is only through the melting of ice.
2. The heat transfer between the copper block and the ice block does not affect the temperature of the copper block.
Solution:
Step 1: Calculate the heat gained by the copper block:
The heat gained by the copper block can be calculated using the formula:
Q = mcΔT
where Q is the heat gained, m is the mass of the copper block, c is the specific heat of copper, and ΔT is the change in temperature.
Given:
Mass of copper block (m) = 2.5 kg
Specific heat of copper (c) = 0.39 J/g°C
Change in temperature (ΔT) = (500 - 0)°C = 500°C
Converting the mass of the copper block from kg to g:
Mass of copper block (m) = 2.5 kg * 1000 g/kg = 2500 g
Substituting the values in the formula:
Q = 2500 g * 0.39 J/g°C * 500°C
Q = 487,500 J
Step 2: Calculate the amount of ice that can melt:
The amount of ice that can melt can be calculated using the formula:
Q = mL
where Q is the heat gained by the copper block, m is the mass of ice melted, and L is the latent heat of fusion of water.
Given:
Heat gained by the copper block (Q) = 487,500 J
Latent heat of fusion of water (L) = 335 J/g
Substituting the values in the formula:
487,500 J = m * 335 J/g
m = 487,500 J / 335 J/g
m ≈ 1455.22 g
Converting the mass of ice melted from g to kg:
Mass of ice melted (m) = 1455.22 g / 1000 g/kg
m ≈ 1.46 kg
Therefore, the maximum amount of ice that can melt is approximately 1.46 kg.
Mass of copper block = 2.5 kg
Temperature of copper block = 500°C
Specific heat of copper = 0.39 J/g°C
Latent heat of fusion of water = 335 J/g
To find:
Maximum amount of ice that can melt in kg
Assumptions:
1. The heat transfer between the copper block and the ice block is only through the melting of ice.
2. The heat transfer between the copper block and the ice block does not affect the temperature of the copper block.
Solution:
Step 1: Calculate the heat gained by the copper block:
The heat gained by the copper block can be calculated using the formula:
Q = mcΔT
where Q is the heat gained, m is the mass of the copper block, c is the specific heat of copper, and ΔT is the change in temperature.
Given:
Mass of copper block (m) = 2.5 kg
Specific heat of copper (c) = 0.39 J/g°C
Change in temperature (ΔT) = (500 - 0)°C = 500°C
Converting the mass of the copper block from kg to g:
Mass of copper block (m) = 2.5 kg * 1000 g/kg = 2500 g
Substituting the values in the formula:
Q = 2500 g * 0.39 J/g°C * 500°C
Q = 487,500 J
Step 2: Calculate the amount of ice that can melt:
The amount of ice that can melt can be calculated using the formula:
Q = mL
where Q is the heat gained by the copper block, m is the mass of ice melted, and L is the latent heat of fusion of water.
Given:
Heat gained by the copper block (Q) = 487,500 J
Latent heat of fusion of water (L) = 335 J/g
Substituting the values in the formula:
487,500 J = m * 335 J/g
m = 487,500 J / 335 J/g
m ≈ 1455.22 g
Converting the mass of ice melted from g to kg:
Mass of ice melted (m) = 1455.22 g / 1000 g/kg
m ≈ 1.46 kg
Therefore, the maximum amount of ice that can melt is approximately 1.46 kg.
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A copper block of mass 2.5 kg is heated in a furnace to a temperature of500Cand then placed on large ice block. The maximum amount (in kg) of ice that can melt is (Specific heat of copper=0.39Jg-1C-1, latent heat of fusion of water=335Jg-1)Correct answer is '1.46'. Can you explain this answer?
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A copper block of mass 2.5 kg is heated in a furnace to a temperature of500Cand then placed on large ice block. The maximum amount (in kg) of ice that can melt is (Specific heat of copper=0.39Jg-1C-1, latent heat of fusion of water=335Jg-1)Correct answer is '1.46'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A copper block of mass 2.5 kg is heated in a furnace to a temperature of500Cand then placed on large ice block. The maximum amount (in kg) of ice that can melt is (Specific heat of copper=0.39Jg-1C-1, latent heat of fusion of water=335Jg-1)Correct answer is '1.46'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A copper block of mass 2.5 kg is heated in a furnace to a temperature of500Cand then placed on large ice block. The maximum amount (in kg) of ice that can melt is (Specific heat of copper=0.39Jg-1C-1, latent heat of fusion of water=335Jg-1)Correct answer is '1.46'. Can you explain this answer?.
A copper block of mass 2.5 kg is heated in a furnace to a temperature of500Cand then placed on large ice block. The maximum amount (in kg) of ice that can melt is (Specific heat of copper=0.39Jg-1C-1, latent heat of fusion of water=335Jg-1)Correct answer is '1.46'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A copper block of mass 2.5 kg is heated in a furnace to a temperature of500Cand then placed on large ice block. The maximum amount (in kg) of ice that can melt is (Specific heat of copper=0.39Jg-1C-1, latent heat of fusion of water=335Jg-1)Correct answer is '1.46'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A copper block of mass 2.5 kg is heated in a furnace to a temperature of500Cand then placed on large ice block. The maximum amount (in kg) of ice that can melt is (Specific heat of copper=0.39Jg-1C-1, latent heat of fusion of water=335Jg-1)Correct answer is '1.46'. Can you explain this answer?.
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A copper block of mass 2.5 kg is heated in a furnace to a temperature of500Cand then placed on large ice block. The maximum amount (in kg) of ice that can melt is (Specific heat of copper=0.39Jg-1C-1, latent heat of fusion of water=335Jg-1)Correct answer is '1.46'. Can you explain this answer?, a detailed solution for A copper block of mass 2.5 kg is heated in a furnace to a temperature of500Cand then placed on large ice block. The maximum amount (in kg) of ice that can melt is (Specific heat of copper=0.39Jg-1C-1, latent heat of fusion of water=335Jg-1)Correct answer is '1.46'. Can you explain this answer? has been provided alongside types of A copper block of mass 2.5 kg is heated in a furnace to a temperature of500Cand then placed on large ice block. The maximum amount (in kg) of ice that can melt is (Specific heat of copper=0.39Jg-1C-1, latent heat of fusion of water=335Jg-1)Correct answer is '1.46'. Can you explain this answer? theory, EduRev gives you an
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