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A copper block of mass 5.0 kg is heated to a temperature of 500°C and is placed on a large ice block. What is the maximum amount of ice that can melt?
[Specific heat of copper: 0.39 J g-1°C-1 and latent heat of fusion of water: 335 J g-1]
[Specific heat of copper: 0.39 J g-1°C-1 and latent heat of fusion of water: 335 J g-1]
- a)1.5 kg
- b)5.8 kg
- c)2.9 kg
- d)3.8 kg
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
A copper block of mass 5.0 kg is heated to a temperature of 500°C ...
To solve this problem, we need to use the equation:
Q = mcΔT
where Q is the heat energy transferred, m is the mass of the copper block, c is the specific heat capacity of copper, and ΔT is the change in temperature.
First, we need to find the heat energy transferred. We can do this by using the equation:
Q = mcΔT
where m is the mass of the copper block (5.0 kg), c is the specific heat capacity of copper (390 J/kg°C), and ΔT is the change in temperature.
ΔT = Tf - Ti
where Tf is the final temperature (500°C) and Ti is the initial temperature (assuming room temperature, which is around 25°C).
ΔT = 500°C - 25°C = 475°C
Now we can substitute the values into the equation:
Q = (5.0 kg)(390 J/kg°C)(475°C)
Q = 924,750 J
Therefore, the heat energy transferred to the copper block is 924,750 Joules.
Q = mcΔT
where Q is the heat energy transferred, m is the mass of the copper block, c is the specific heat capacity of copper, and ΔT is the change in temperature.
First, we need to find the heat energy transferred. We can do this by using the equation:
Q = mcΔT
where m is the mass of the copper block (5.0 kg), c is the specific heat capacity of copper (390 J/kg°C), and ΔT is the change in temperature.
ΔT = Tf - Ti
where Tf is the final temperature (500°C) and Ti is the initial temperature (assuming room temperature, which is around 25°C).
ΔT = 500°C - 25°C = 475°C
Now we can substitute the values into the equation:
Q = (5.0 kg)(390 J/kg°C)(475°C)
Q = 924,750 J
Therefore, the heat energy transferred to the copper block is 924,750 Joules.
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Community Answer
A copper block of mass 5.0 kg is heated to a temperature of 500°C ...
Heat given by block to get 0°C temperature
= 975 x 103 J
Heat absorbed by ice to melt m mass
= 975 x 103 J
Heat absorbed by ice to melt m mass
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A copper block of mass 5.0 kg is heated to a temperature of 500°C and is placed on a large ice block. What is the maximum amount of ice that can melt?[Specific heat of copper: 0.39 J g-1°C-1 and latent heat of fusion of water: 335 J g-1]a)1.5 kgb)5.8 kgc)2.9 kgd)3.8 kgCorrect answer is option 'C'. Can you explain this answer?
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A copper block of mass 5.0 kg is heated to a temperature of 500°C and is placed on a large ice block. What is the maximum amount of ice that can melt?[Specific heat of copper: 0.39 J g-1°C-1 and latent heat of fusion of water: 335 J g-1]a)1.5 kgb)5.8 kgc)2.9 kgd)3.8 kgCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A copper block of mass 5.0 kg is heated to a temperature of 500°C and is placed on a large ice block. What is the maximum amount of ice that can melt?[Specific heat of copper: 0.39 J g-1°C-1 and latent heat of fusion of water: 335 J g-1]a)1.5 kgb)5.8 kgc)2.9 kgd)3.8 kgCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A copper block of mass 5.0 kg is heated to a temperature of 500°C and is placed on a large ice block. What is the maximum amount of ice that can melt?[Specific heat of copper: 0.39 J g-1°C-1 and latent heat of fusion of water: 335 J g-1]a)1.5 kgb)5.8 kgc)2.9 kgd)3.8 kgCorrect answer is option 'C'. Can you explain this answer?.
A copper block of mass 5.0 kg is heated to a temperature of 500°C and is placed on a large ice block. What is the maximum amount of ice that can melt?[Specific heat of copper: 0.39 J g-1°C-1 and latent heat of fusion of water: 335 J g-1]a)1.5 kgb)5.8 kgc)2.9 kgd)3.8 kgCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A copper block of mass 5.0 kg is heated to a temperature of 500°C and is placed on a large ice block. What is the maximum amount of ice that can melt?[Specific heat of copper: 0.39 J g-1°C-1 and latent heat of fusion of water: 335 J g-1]a)1.5 kgb)5.8 kgc)2.9 kgd)3.8 kgCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A copper block of mass 5.0 kg is heated to a temperature of 500°C and is placed on a large ice block. What is the maximum amount of ice that can melt?[Specific heat of copper: 0.39 J g-1°C-1 and latent heat of fusion of water: 335 J g-1]a)1.5 kgb)5.8 kgc)2.9 kgd)3.8 kgCorrect answer is option 'C'. Can you explain this answer?.
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A copper block of mass 5.0 kg is heated to a temperature of 500°C and is placed on a large ice block. What is the maximum amount of ice that can melt?[Specific heat of copper: 0.39 J g-1°C-1 and latent heat of fusion of water: 335 J g-1]a)1.5 kgb)5.8 kgc)2.9 kgd)3.8 kgCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A copper block of mass 5.0 kg is heated to a temperature of 500°C and is placed on a large ice block. What is the maximum amount of ice that can melt?[Specific heat of copper: 0.39 J g-1°C-1 and latent heat of fusion of water: 335 J g-1]a)1.5 kgb)5.8 kgc)2.9 kgd)3.8 kgCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A copper block of mass 5.0 kg is heated to a temperature of 500°C and is placed on a large ice block. What is the maximum amount of ice that can melt?[Specific heat of copper: 0.39 J g-1°C-1 and latent heat of fusion of water: 335 J g-1]a)1.5 kgb)5.8 kgc)2.9 kgd)3.8 kgCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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