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Where will the hand of a clock stop if it starts at 2 and makes 3/4 of a revolution, clockwise?
  • a)
    11
  • b)
    5
  • c)
    8
  • d)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Where will the hand of a clock stop if it starts at 2 and makes 3/4 of...
If an hand of click starts at 5 and makes 3/4 of a revolution ,Thus, The hand of a clock at 11
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Where will the hand of a clock stop if it starts at 2 and makes 3/4 of...
Answer:

To solve this question, we need to understand how the hands of a clock move and measure angles.

1. Understanding the movement of clock hands:
- A clock has three hands: the hour hand, the minute hand, and the second hand.
- The hour hand completes one full revolution in 12 hours.
- The minute hand completes one full revolution in 60 minutes.
- The second hand completes one full revolution in 60 seconds.

2. Measuring angles:
- A clock has 360 degrees in a full circle.
- Since the hour hand completes one full revolution in 12 hours (or 720 minutes), it covers 360 degrees in 720 minutes.
- Therefore, the hour hand moves 0.5 degrees per minute (360 degrees divided by 720 minutes).

Now, let's solve the given question:

- The hand starts at 2, which means it is the hour hand.
- The hand needs to make 3/4 of a revolution clockwise.
- 3/4 of a revolution is equal to 270 degrees (3/4 x 360 degrees).
- Since the hour hand moves at a rate of 0.5 degrees per minute, we can calculate the time it takes to cover 270 degrees.

Time taken = (270 degrees) / (0.5 degrees per minute)
= 540 minutes

Therefore, the hand will stop after 540 minutes.

To determine the exact position, we need to convert minutes into hours.

- 540 minutes is equal to 9 hours (since 60 minutes = 1 hour).
- Adding 9 hours to the starting position of 2, we get 11.

Hence, the correct answer is option 'A' - 11.
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Where will the hand of a clock stop if it starts at 2 and makes 3/4 of a revolution, clockwise?a)11b)5c)8d)None of theseCorrect answer is option 'A'. Can you explain this answer?
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