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The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows :Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84, loge 10 = 2.3a)The half life of the reaction is 75 min.b)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatory.d)The angle would be 7.5° at half time.Correct answer is option 'A,B,D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows :Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84, loge 10 = 2.3a)The half life of the reaction is 75 min.b)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatory.d)The angle would be 7.5° at half time.Correct answer is option 'A,B,D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows :Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84, loge 10 = 2.3a)The half life of the reaction is 75 min.b)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatory.d)The angle would be 7.5° at half time.Correct answer is option 'A,B,D'. Can you explain this answer?.

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Here you can find the meaning of The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows :Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84, loge 10 = 2.3a)The half life of the reaction is 75 min.b)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatory.d)The angle would be 7.5° at half time.Correct answer is option 'A,B,D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows :Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84, loge 10 = 2.3a)The half life of the reaction is 75 min.b)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatory.d)The angle would be 7.5° at half time.Correct answer is option 'A,B,D'. Can you explain this answer?, a detailed solution for The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows :Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84, loge 10 = 2.3a)The half life of the reaction is 75 min.b)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatory.d)The angle would be 7.5° at half time.Correct answer is option 'A,B,D'. Can you explain this answer? has been provided alongside types of The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows :Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84, loge 10 = 2.3a)The half life of the reaction is 75 min.b)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatory.d)The angle would be 7.5° at half time.Correct answer is option 'A,B,D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows :Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84, loge 10 = 2.3a)The half life of the reaction is 75 min.b)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatory.d)The angle would be 7.5° at half time.Correct answer is option 'A,B,D'. Can you explain this answer? tests, examples and also practice JEE tests.