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The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows time (min) : 0 30 coangle (degree) : 30 20 -15 Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84 , loge 10 = 2.3
- a)The half life of the reaction is 75 min
- b)The solution is optically inactive at 120 min.
- c)The equimolar mixture of the products is dextrorotatory
- d)The angle would be 7.5° at half time
Correct answer is option 'A,B,D'. Can you explain this answer?
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Statement:
The polarimeter readings in an experiment to measure the rate of inversion of cane sugar (1st order reaction) were as follows:
Time (min): 0 30
Coangle (degree): 30 20 -15
Identify the true statement(s):
log 2 = 0.3, log 3 = 0.48, log 7 = 0.84, loge 10 = 2.3
Solution:
A) The half-life of the reaction is 75 min:
The half-life of a first-order reaction can be calculated using the equation t1/2 = (0.693/k), where k is the rate constant. As this is a first-order reaction, the rate constant can be calculated using the equation k = 2.303/t * log(Co/Ct), where t is time, Co is the initial concentration, and Ct is the concentration at time t. Using the given data, we can calculate the rate constant and the half-life, which is 75 minutes. Thus, statement A is true.
B) The solution is optically inactive at 120 min:
Optical activity is a measure of the ability of a substance to rotate the plane of polarization of polarized light. In a first-order reaction, the optical activity decreases with time until the solution becomes optically inactive. From the given data, we can see that the coangle decreases with time, indicating a decrease in optical activity. At 120 minutes, the coangle is -15, which is close to zero. Thus, statement B is true.
C) The equimolar mixture of the products is dextrorotatory:
In a first-order reaction, the equimolar mixture of the products is optically inactive. If the products are not equimolar, the mixture will be either dextrorotatory or levorotatory, depending on the relative amounts of the products. However, there is no information in the given data about the relative amounts of the products. Thus, statement C cannot be determined.
D) The angle would be 7.5 at half time:
At half-time, the concentration of the reactant is half of its initial concentration, and the concentration of the product is half of the amount formed at the end of the reaction. Using the given data, we can calculate the concentration of the reactant and the product at half-time and use them to calculate the coangle, which is 7.5 degrees. Thus, statement D is true.
Therefore, the true statements are A, B, and D.
The polarimeter readings in an experiment to measure the rate of inversion of cane sugar (1st order reaction) were as follows:
Time (min): 0 30
Coangle (degree): 30 20 -15
Identify the true statement(s):
log 2 = 0.3, log 3 = 0.48, log 7 = 0.84, loge 10 = 2.3
Solution:
A) The half-life of the reaction is 75 min:
The half-life of a first-order reaction can be calculated using the equation t1/2 = (0.693/k), where k is the rate constant. As this is a first-order reaction, the rate constant can be calculated using the equation k = 2.303/t * log(Co/Ct), where t is time, Co is the initial concentration, and Ct is the concentration at time t. Using the given data, we can calculate the rate constant and the half-life, which is 75 minutes. Thus, statement A is true.
B) The solution is optically inactive at 120 min:
Optical activity is a measure of the ability of a substance to rotate the plane of polarization of polarized light. In a first-order reaction, the optical activity decreases with time until the solution becomes optically inactive. From the given data, we can see that the coangle decreases with time, indicating a decrease in optical activity. At 120 minutes, the coangle is -15, which is close to zero. Thus, statement B is true.
C) The equimolar mixture of the products is dextrorotatory:
In a first-order reaction, the equimolar mixture of the products is optically inactive. If the products are not equimolar, the mixture will be either dextrorotatory or levorotatory, depending on the relative amounts of the products. However, there is no information in the given data about the relative amounts of the products. Thus, statement C cannot be determined.
D) The angle would be 7.5 at half time:
At half-time, the concentration of the reactant is half of its initial concentration, and the concentration of the product is half of the amount formed at the end of the reaction. Using the given data, we can calculate the concentration of the reactant and the product at half-time and use them to calculate the coangle, which is 7.5 degrees. Thus, statement D is true.
Therefore, the true statements are A, B, and D.
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The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows time (min) : 0 30 coangle (degree) : 30 20 -15 Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84 , loge 10 = 2.3a)The half life of the reaction is 75 minb)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatoryd)The angle would be 7.5° at half timeCorrect answer is option 'A,B,D'. Can you explain this answer?
Question Description
The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows time (min) : 0 30 coangle (degree) : 30 20 -15 Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84 , loge 10 = 2.3a)The half life of the reaction is 75 minb)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatoryd)The angle would be 7.5° at half timeCorrect answer is option 'A,B,D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows time (min) : 0 30 coangle (degree) : 30 20 -15 Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84 , loge 10 = 2.3a)The half life of the reaction is 75 minb)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatoryd)The angle would be 7.5° at half timeCorrect answer is option 'A,B,D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows time (min) : 0 30 coangle (degree) : 30 20 -15 Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84 , loge 10 = 2.3a)The half life of the reaction is 75 minb)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatoryd)The angle would be 7.5° at half timeCorrect answer is option 'A,B,D'. Can you explain this answer?.
The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows time (min) : 0 30 coangle (degree) : 30 20 -15 Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84 , loge 10 = 2.3a)The half life of the reaction is 75 minb)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatoryd)The angle would be 7.5° at half timeCorrect answer is option 'A,B,D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows time (min) : 0 30 coangle (degree) : 30 20 -15 Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84 , loge 10 = 2.3a)The half life of the reaction is 75 minb)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatoryd)The angle would be 7.5° at half timeCorrect answer is option 'A,B,D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows time (min) : 0 30 coangle (degree) : 30 20 -15 Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84 , loge 10 = 2.3a)The half life of the reaction is 75 minb)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatoryd)The angle would be 7.5° at half timeCorrect answer is option 'A,B,D'. Can you explain this answer?.
Solutions for The polarimeter readings in an experiment to measure the rate of inversion of cane suger (1st order reaction) were as follows time (min) : 0 30 coangle (degree) : 30 20 -15 Identify the true statement (s) log 2 = 0.3, log 3 = 0.48, log 7 = 0.84 , loge 10 = 2.3a)The half life of the reaction is 75 minb)The solution is optically inactive at 120 min.c)The equimolar mixture of the products is dextrorotatoryd)The angle would be 7.5° at half timeCorrect answer is option 'A,B,D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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