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CH 3 H - C CH 2 -CH 2 -CH 2 -CH 3 S-2-chloro hexane hv (x). (x) = total number of di chloro product (excluding stereoisomers?
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CH 3 H - C CH 2 -CH 2 -CH 2 -CH 3 S-2-chloro hexane hv (x). (x) = tota...
Reaction: CH3CH(CH2CH2CH2)2CH3 + S2Cl2 → CH3CH(Cl)CH(Cl)CH2CH2CH2CH3 + HCl + S

Explanation:
- In the given reaction, 2-chlorohexane (CH3CH(Cl)CH2CH2CH2CH3) is formed as the product along with HCl and S.
- The reaction involves the substitution of two chlorine atoms (Cl) for two hydrogen atoms (H) in 2-hexane molecule.
- The chlorine atoms in S2Cl2 act as electrophiles and attack the carbon atoms of the alkane molecule.
- The product formed is a mixture of stereoisomers due to the presence of chiral carbon atoms in the hexane molecule.
- However, the question specifies to exclude stereoisomers from the count of dichloro product.
- Hence, only the total number of dichloro product (excluding stereoisomers) is asked to be determined.

Total number of dichloro product (excluding stereoisomers):
- The given hexane molecule has six carbon atoms, out of which two are chiral centers.
- The two chiral carbon atoms result in four stereoisomers of the product.
- However, as specified in the question, we have to exclude stereoisomers from the count.
- Therefore, only one dichloro product is formed, irrespective of the stereochemistry.
- Hence, the total number of dichloro product (excluding stereoisomers) is 1.
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CH 3 H - C CH 2 -CH 2 -CH 2 -CH 3 S-2-chloro hexane hv (x). (x) = total number of di chloro product (excluding stereoisomers?
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