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An object dropped from a cliff falls with a constant acceleration of 10m/s2. Find its speed 5s after it was dropped.?
Most Upvoted Answer
An object dropped from a cliff falls with a constant acceleration of 1...
V = gt, equation for vertical fall when body is starting from rest.... (u =0)...
V = 10 * 5 = 50 m/s....
Community Answer
An object dropped from a cliff falls with a constant acceleration of 1...
Given


  • Acceleration = 10m/s^2 (constant)

  • Time = 5s (after it was dropped)

  • Initial Velocity = 0m/s (since it was dropped from rest)



Formula


  • Final Velocity (v) = Initial Velocity (u) + (Acceleration (a) * Time (t))



Solution

Using the formula, we can calculate the final velocity:


  • v = u + at

  • v = 0 + (10 x 5)

  • v = 50 m/s



Answer

The speed of the object 5 seconds after it was dropped is 50 m/s.


Explanation

When an object is dropped from a height, it experiences a constant acceleration due to gravity. This acceleration is always equal to 9.8 m/s^2 (or 10 m/s^2, rounded off). This means that every second, the object's velocity increases by 10 m/s. So, after 5 seconds, the object's velocity would have increased by 50 m/s (10 x 5 = 50). Since the object was dropped from rest, its initial velocity is 0 m/s. Therefore, the final velocity after 5 seconds is 50 m/s.
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An object dropped from a cliff falls with a constant acceleration of 10m/s2. Find its speed 5s after it was dropped.?
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