Introduction:
When an object is dropped from a cliff, it falls due to the force of gravity. The acceleration experienced by a falling object is constant and equal to the acceleration due to gravity, which is approximately 10 m/s² on Earth. In this question, we are given that the object falls with a constant acceleration of 10 m/s² and we need to find its speed after 5 seconds.

Given:
- Acceleration (a) = 10 m/s²
- Time (t) = 5 seconds

Calculating the speed:
To find the speed of the object after 5 seconds, we can use the formula:

v = u + at

where:
- v is the final velocity (speed)
- u is the initial velocity (which is 0 in this case since the object is dropped)
- a is the acceleration (given as 10 m/s²)
- t is the time (given as 5 seconds)

Substituting the values:
Since the initial velocity (u) is 0, the equation simplifies to:

v = at

Substituting the values of acceleration (a = 10 m/s²) and time (t = 5 seconds) into the equation, we get:

v = 10 m/s² * 5 s

Solving the equation:
Multiplying the acceleration (10 m/s²) by the time (5 seconds), we get:

v = 50 m/s

Therefore, the speed of the object after 5 seconds of falling is 50 m/s.

Explanation:
When an object is dropped from a height, it accelerates due to the force of gravity. The acceleration remains constant throughout the fall and is equal to the acceleration due to gravity, which is approximately 10 m/s². This means that for every second the object falls, its speed increases by 10 m/s.

In this question, we are given that the object falls with a constant acceleration of 10 m/s². Using the formula v = at, we can calculate the speed of the object after 5 seconds. By substituting the values of acceleration (10 m/s²) and time (5 seconds) into the equation, we find that the speed of the object after 5 seconds is 50 m/s.

Therefore, after 5 seconds of falling, the object will have a speed of 50 m/s.