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An object is dropped from rest at a height of 150m & simultaneously another object is dropped from rest at a height of 100m. what is the difference between their heights after 2 sec if both the object is dropped with same acceleration ? how does the difference in heights vary with time?
Verified Answer
An object is dropped from rest at a height of 150m & simultaneously an...
for Ist object. u =0. t=2sec
the object is 150m abobe the ground
a =g= 10 (9.8)
s=ut+1/2at^2
s=0x2+1/2x10x2x2
s=20
AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 150-20=130M
for IInd object. u =0. t=2sec
a =g= 10 (9.8)
the object is 100m abobe the ground
a =g= 10 (9.8)
s=ut+1/2at^2
s=0x2+1/2x10x2x2
s=20
AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 100-20=80M
THE DISTANCE BETWEEN THE OBJECTS AFTER 2 SEC
=130-80=50m
This question is part of UPSC exam. View all Class 9 courses
Most Upvoted Answer
An object is dropped from rest at a height of 150m & simultaneously an...
When an object is dropped from rest at a certain height, it falls freely under the influence of gravity. The acceleration due to gravity is approximately 9.8 m/s^2.
Using the equation of motion for free fall:
h = (1/2)gt^2
Where:
h = height (150m)
g = acceleration due to gravity (9.8 m/s^2)
t = time
Rearranging the equation to solve for time:
2h = gt^2
t^2 = (2h) / g
t = sqrt((2h) / g)
Substituting the values:
t = sqrt((2 * 150) / 9.8)
t = sqrt(300 / 9.8)
t ≈ sqrt(30.61)
t ≈ 5.52 seconds
Therefore, it would take approximately 5.52 seconds for the object to fall from rest at a height of 150m.
Using the equation of motion for free fall:
h = (1/2)gt^2
Where:
h = height (150m)
g = acceleration due to gravity (9.8 m/s^2)
t = time
Rearranging the equation to solve for time:
2h = gt^2
t^2 = (2h) / g
t = sqrt((2h) / g)
Substituting the values:
t = sqrt((2 * 150) / 9.8)
t = sqrt(300 / 9.8)
t ≈ sqrt(30.61)
t ≈ 5.52 seconds
Therefore, it would take approximately 5.52 seconds for the object to fall from rest at a height of 150m.
Community Answer
An object is dropped from rest at a height of 150m & simultaneously an...
For 1st object u=0 t=2 sec
the object is 150m abode the ground
a=g=10 ( 9.8)
s= ut +1/2at²
s= 0×2+1/2×10×2×2
s= 20
After 2 second the distance between the object and ground is 150-20 = 130 m
For 2nd object u=0 t=2 sec
a=g=10 (9.8 )
the object is 100 m abode the ground
a=g=10 (9.8)
s=ut + 1/2 at²
s=0×2+1/2×10×2×2
s= 20
After 2 second the distance between the object and ground is 100-30 = 80
The distance between the object after 2 sec = 130-80
= 50 ans
the object is 150m abode the ground
a=g=10 ( 9.8)
s= ut +1/2at²
s= 0×2+1/2×10×2×2
s= 20
After 2 second the distance between the object and ground is 150-20 = 130 m
For 2nd object u=0 t=2 sec
a=g=10 (9.8 )
the object is 100 m abode the ground
a=g=10 (9.8)
s=ut + 1/2 at²
s=0×2+1/2×10×2×2
s= 20
After 2 second the distance between the object and ground is 100-30 = 80
The distance between the object after 2 sec = 130-80
= 50 ans
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An object is dropped from rest at a height of 150m & simultaneously another object is dropped from rest at a height of 100m. what is the difference between their heights after 2 sec if both the object is dropped with same acceleration ? how does the difference in heights vary with time?
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An object is dropped from rest at a height of 150m & simultaneously another object is dropped from rest at a height of 100m. what is the difference between their heights after 2 sec if both the object is dropped with same acceleration ? how does the difference in heights vary with time? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about An object is dropped from rest at a height of 150m & simultaneously another object is dropped from rest at a height of 100m. what is the difference between their heights after 2 sec if both the object is dropped with same acceleration ? how does the difference in heights vary with time? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object is dropped from rest at a height of 150m & simultaneously another object is dropped from rest at a height of 100m. what is the difference between their heights after 2 sec if both the object is dropped with same acceleration ? how does the difference in heights vary with time?.
An object is dropped from rest at a height of 150m & simultaneously another object is dropped from rest at a height of 100m. what is the difference between their heights after 2 sec if both the object is dropped with same acceleration ? how does the difference in heights vary with time? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about An object is dropped from rest at a height of 150m & simultaneously another object is dropped from rest at a height of 100m. what is the difference between their heights after 2 sec if both the object is dropped with same acceleration ? how does the difference in heights vary with time? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An object is dropped from rest at a height of 150m & simultaneously another object is dropped from rest at a height of 100m. what is the difference between their heights after 2 sec if both the object is dropped with same acceleration ? how does the difference in heights vary with time?.
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