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A sum of money doubles itself in 3 years at C.I., when the interest is compounded annually. In how many years will it amount to 16 times of itself?

  • a)
    6 years

  • b)
    8 years

  • c)
    12 years

  • d)
    16 years

Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A sum of money doubles itself in 3 years at C.I., when the interest is...
Given, the sum of money doubles itself in 3 years at C.I.
Let the principal amount be P and the rate of interest be r.

After 3 years, the amount becomes 2P.

Using the formula for compound interest, we have:
2P = P(1 + r/100)^3
=> (1 + r/100)^3 = 2
=> 1 + r/100 = ∛2
=> r/100 = ∛2 - 1
=> r = 100(∛2 - 1)

Now, we need to find the number of years it will take for the amount to become 16 times the original amount.

Let the required number of years be n.

Using the same formula for compound interest, we have:
16P = P(1 + r/100)^n
=> (1 + r/100)^n = 16
=> n log(1 + r/100) = log 16
=> n = log 16 / log(1 + r/100)

Substituting the value of r, we get:
n = log 16 / log(1 + 100(∛2 - 1)/100)
=> n ≈ 12 years

Therefore, the correct answer is option (c) 12 years.
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Community Answer
A sum of money doubles itself in 3 years at C.I., when the interest is...
A sum of money doubles itself in 3 years at compound interest. It will amount to 16 times itself at the same rate of interest is: 9 years + 3 years = 12 years (C)
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A sum of money doubles itself in 3 years at C.I., when the interest is compounded annually. In how many years will it amount to 16 times of itself?a)6 yearsb)8 yearsc)12 yearsd)16 yearsCorrect answer is option 'C'. Can you explain this answer?
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