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Figure shows block A of mass 0.2 kg sliding to the right over a frictionless elevated surface at a speed of 10 m/s. The block undergoes a collision with stationary block B, which is connected to a nondeformed springof spring constant 1000 Nm–1. The coefficient of restitution between the blocks is 0.5. After the collision, block B oscillates in SHM with a period of 0.2 s, and block A slides off the left end of the elevated surface, landing a distance d from the base of that surface after falling height 5m.(use π2 = 10; g = 10 m/s2) Assume that the springdoes not affect the collision.The distance d will be equal to -a)2mb)2.5mc)4md)6.25mCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Figure shows block A of mass 0.2 kg sliding to the right over a frictionless elevated surface at a speed of 10 m/s. The block undergoes a collision with stationary block B, which is connected to a nondeformed springof spring constant 1000 Nm–1. The coefficient of restitution between the blocks is 0.5. After the collision, block B oscillates in SHM with a period of 0.2 s, and block A slides off the left end of the elevated surface, landing a distance d from the base of that surface after falling height 5m.(use π2 = 10; g = 10 m/s2) Assume that the springdoes not affect the collision.The distance d will be equal to -a)2mb)2.5mc)4md)6.25mCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Figure shows block A of mass 0.2 kg sliding to the right over a frictionless elevated surface at a speed of 10 m/s. The block undergoes a collision with stationary block B, which is connected to a nondeformed springof spring constant 1000 Nm–1. The coefficient of restitution between the blocks is 0.5. After the collision, block B oscillates in SHM with a period of 0.2 s, and block A slides off the left end of the elevated surface, landing a distance d from the base of that surface after falling height 5m.(use π2 = 10; g = 10 m/s2) Assume that the springdoes not affect the collision.The distance d will be equal to -a)2mb)2.5mc)4md)6.25mCorrect answer is option 'B'. Can you explain this answer?.

Solutions for Figure shows block A of mass 0.2 kg sliding to the right over a frictionless elevated surface at a speed of 10 m/s. The block undergoes a collision with stationary block B, which is connected to a nondeformed springof spring constant 1000 Nm–1. The coefficient of restitution between the blocks is 0.5. After the collision, block B oscillates in SHM with a period of 0.2 s, and block A slides off the left end of the elevated surface, landing a distance d from the base of that surface after falling height 5m.(use π2 = 10; g = 10 m/s2) Assume that the springdoes not affect the collision.The distance d will be equal to -a)2mb)2.5mc)4md)6.25mCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of Figure shows block A of mass 0.2 kg sliding to the right over a frictionless elevated surface at a speed of 10 m/s. The block undergoes a collision with stationary block B, which is connected to a nondeformed springof spring constant 1000 Nm–1. The coefficient of restitution between the blocks is 0.5. After the collision, block B oscillates in SHM with a period of 0.2 s, and block A slides off the left end of the elevated surface, landing a distance d from the base of that surface after falling height 5m.(use π2 = 10; g = 10 m/s2) Assume that the springdoes not affect the collision.The distance d will be equal to -a)2mb)2.5mc)4md)6.25mCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Figure shows block A of mass 0.2 kg sliding to the right over a frictionless elevated surface at a speed of 10 m/s. The block undergoes a collision with stationary block B, which is connected to a nondeformed springof spring constant 1000 Nm–1. The coefficient of restitution between the blocks is 0.5. After the collision, block B oscillates in SHM with a period of 0.2 s, and block A slides off the left end of the elevated surface, landing a distance d from the base of that surface after falling height 5m.(use π2 = 10; g = 10 m/s2) Assume that the springdoes not affect the collision.The distance d will be equal to -a)2mb)2.5mc)4md)6.25mCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Figure shows block A of mass 0.2 kg sliding to the right over a frictionless elevated surface at a speed of 10 m/s. The block undergoes a collision with stationary block B, which is connected to a nondeformed springof spring constant 1000 Nm–1. The coefficient of restitution between the blocks is 0.5. After the collision, block B oscillates in SHM with a period of 0.2 s, and block A slides off the left end of the elevated surface, landing a distance d from the base of that surface after falling height 5m.(use π2 = 10; g = 10 m/s2) Assume that the springdoes not affect the collision.The distance d will be equal to -a)2mb)2.5mc)4md)6.25mCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Figure shows block A of mass 0.2 kg sliding to the right over a frictionless elevated surface at a speed of 10 m/s. The block undergoes a collision with stationary block B, which is connected to a nondeformed springof spring constant 1000 Nm–1. The coefficient of restitution between the blocks is 0.5. After the collision, block B oscillates in SHM with a period of 0.2 s, and block A slides off the left end of the elevated surface, landing a distance d from the base of that surface after falling height 5m.(use π2 = 10; g = 10 m/s2) Assume that the springdoes not affect the collision.The distance d will be equal to -a)2mb)2.5mc)4md)6.25mCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Figure shows block A of mass 0.2 kg sliding to the right over a frictionless elevated surface at a speed of 10 m/s. The block undergoes a collision with stationary block B, which is connected to a nondeformed springof spring constant 1000 Nm–1. The coefficient of restitution between the blocks is 0.5. After the collision, block B oscillates in SHM with a period of 0.2 s, and block A slides off the left end of the elevated surface, landing a distance d from the base of that surface after falling height 5m.(use π2 = 10; g = 10 m/s2) Assume that the springdoes not affect the collision.The distance d will be equal to -a)2mb)2.5mc)4md)6.25mCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.