The equilibrium constant for the reaction Br2(l) + Cl2(g) 2Br Cl(g) at 27anddeg;C is kp = 1 atm. In a closed container of volume 164 L initially 10 moles of Cl2are present at 27andordm;C.What minimum mass of Br2(l) (in grams) must be introduced into this container so that above equilibrium is maintainedat total pressure of 2.25 atm. Vapour pressure of Br2(l) at 27andordm;C is 0.25 atm. Assume that volume occupied byliquid is negligible. [R = 0.082 L atm mole-1K-1, Atomic mass of bromine = 80].Correct answer is '400'. Can you explain this answer?

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The equilibrium constant for the reaction Br₂(l) + Cl₂(g)

2Br Cl(g) at 27°C is kp = 1 atm. In a closed container of volume 164 L initially 10 moles of Cl₂ are present at 27ºC. What minimum mass of Br₂(l) (in grams) must be introduced into this container so that above equilibrium is maintained at total pressure of 2.25 atm. Vapour pressure of Br₂(l) at 27ºC is 0.25 atm. Assume that volume occupied by liquid is negligible. [R = 0.082 L atm mole^-1 K^-1, Atomic mass of bromine = 80].

Correct answer is '400'. Can you explain this answer?

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The equilibrium constant for the reaction Br2(l) + Cl2(g) 2Br Cl(g) at...

To maintain the mentioned equilibrium there must be some (negligible) mass of Br₂(l) at equilibrium so there will be an equilibrium

so some Br₂(ℓ) will be required for this conversion (into vapour) moles of Br₂(ℓ) required for above equilibrium

Now for equilibrium

otal gaseous moles = (10 + x) {Let x be moles of Br₂ (ℓ) required just to maintain above equilibrium}
we have

So,

⇒

⇒ 8x² = 100 - x² ⇒ 9x² = 100
so x = 10/3
Hence total moles of Br₂(ℓ) required to maintain both of above equilibria

so mass of Br₂ (ℓ) required = (80 g/mole) (5 mole) = 400 gm

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The equilibrium constant for the reaction Br2(l) + Cl2(g) 2Br Cl(g) at 27°C is kp = 1 atm. In a closed container of volume 164 L initially 10 moles of Cl2are present at 27ºC.What minimum mass of Br2(l) (in grams) must be introduced into this container so that above equilibrium is maintainedat total pressure of 2.25 atm. Vapour pressure of Br2(l) at 27ºC is 0.25 atm. Assume that volume occupied byliquid is negligible. [R = 0.082 L atm mole-1K-1, Atomic mass of bromine = 80].Correct answer is '400'. Can you explain this answer?

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The equilibrium constant for the reaction Br2(l) + Cl2(g) 2Br Cl(g) at 27°C is kp = 1 atm. In a closed container of volume 164 L initially 10 moles of Cl2are present at 27ºC.What minimum mass of Br2(l) (in grams) must be introduced into this container so that above equilibrium is maintainedat total pressure of 2.25 atm. Vapour pressure of Br2(l) at 27ºC is 0.25 atm. Assume that volume occupied byliquid is negligible. [R = 0.082 L atm mole-1K-1, Atomic mass of bromine = 80].Correct answer is '400'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The equilibrium constant for the reaction Br2(l) + Cl2(g) 2Br Cl(g) at 27°C is kp = 1 atm. In a closed container of volume 164 L initially 10 moles of Cl2are present at 27ºC.What minimum mass of Br2(l) (in grams) must be introduced into this container so that above equilibrium is maintainedat total pressure of 2.25 atm. Vapour pressure of Br2(l) at 27ºC is 0.25 atm. Assume that volume occupied byliquid is negligible. [R = 0.082 L atm mole-1K-1, Atomic mass of bromine = 80].Correct answer is '400'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equilibrium constant for the reaction Br2(l) + Cl2(g) 2Br Cl(g) at 27°C is kp = 1 atm. In a closed container of volume 164 L initially 10 moles of Cl2are present at 27ºC.What minimum mass of Br2(l) (in grams) must be introduced into this container so that above equilibrium is maintainedat total pressure of 2.25 atm. Vapour pressure of Br2(l) at 27ºC is 0.25 atm. Assume that volume occupied byliquid is negligible. [R = 0.082 L atm mole-1K-1, Atomic mass of bromine = 80].Correct answer is '400'. Can you explain this answer?.

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