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Corners are cut off from an equilateral triangle T to produce a regular hexagon H. Then, the ratio of the area of H to the area of T is
  • a)
    2:3
  • b)
    4:5
  • c)
    5:6
  • d)
    3:4
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Corners are cut off from an equilateral triangle T to produce a regul...
The given figure can be divided into 9 regions or equilateral triangles of equal areas as shown below,
Now the hexagon consists of 6 regions and the triangle consists of 9 regions.
Hence the ratio of areas = 6/9 =2:3
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Most Upvoted Answer
Corners are cut off from an equilateral triangle T to produce a regul...
The given figure can be divided into 9 regions or equilateral triangles of equal areas as shown below,
Now the hexagon consists of 6 regions and the triangle consists of 9 regions.
Hence the ratio of areas = 6/9 =2:3
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Corners are cut off from an equilateral triangle T to produce a regular hexagon H. Then, the ratio of the area of H to the area of T isa) 2:3b) 4:5c) 5:6d) 3:4Correct answer is option 'A'. Can you explain this answer?
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