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A mixture comprises water and liquids A and B. The volume of water is 1/3rdof the total mixture and the volume of liquids A and B are in the ratio 5:3. To remove the water, the mixture is passed through a porous medium which completely absorbs the water and partially absorbs liquid A. Altogether this porous medium absorbs 200 ml of the initial mixture. If the ratio of volume of liquids A and B in the residual concentrated mixture becomes 7:9 then find the volume of water absorbed by the porous medium.
  • a)
    60 ml
  • b)
    200/3 ml
  • c)
    80 ml
  • d)
    100 ml
  • e)
    120 ml
Correct answer is option 'E'. Can you explain this answer?
Verified Answer
A mixture comprises water and liquids A and B. The volume of water is...
Liquids A and B are in the ratio 5:3. The volume of water is one-third the total mixture.
Let us assume the volume of the total mixture to be 24x.
Volume of liquid A = 10x
Volume of liquid B = 6x
Volume of water = 8x
The mixture is passed through some medium that absorbs water completely and some quantity of liquid A.
Water absorbed = 8x
Let the amount of liquid A absorbed be y.
8x+y = 200
=> y = 200-8x —(1)
It has been given that (10x-y)/6x = 7/9
Substituting (1), we get,
(10x – 200+8x)/6x = 7/9
(18x-200)/6x = 7/9
162x – 1800=42x
120x = 1800
=> x = 1800/120
Amount of water absorbed = 8*1800/120 = 120 ml.
Therefore, option E is the right answer.
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Most Upvoted Answer
A mixture comprises water and liquids A and B. The volume of water is...
Given information:

- Volume of water in the mixture = 1/3 of the total mixture
- Volume ratio of liquids A and B = 5:3
- Porous medium absorbs completely water and partially liquid A
- Porous medium absorbs 200 ml of the initial mixture
- Ratio of volume of liquids A and B in the residual mixture = 7:9

To find: Volume of water absorbed by the porous medium

Solution:

Let the total volume of the mixture be 3x (since water is 1/3 of the total mixture)

Then, volume of water = x and volume of liquids A and B = 2x (since the ratio of liquids A and B is 5:3)

Let the porous medium absorb y ml of liquid A

Then, the remaining volume of liquid A = 5/8(2x - y) (since porous medium absorbs 3/8 of liquid A)

And the remaining volume of liquid B = 3/8(2x) = 3x/4 (since porous medium absorbs no liquid B)

According to the question, the ratio of volume of liquids A and B in the residual mixture is 7:9. Therefore,

(5/8)(2x - y)/(3x/4) = 7/9

Simplifying the above equation, we get:

y = (40/27)x

Now, the volume of the initial mixture absorbed by the porous medium = volume of water absorbed + volume of liquid A absorbed

200 = x + y

Substituting the value of y, we get:

200 = x + (40/27)x

Solving for x, we get:

x = 120

Therefore, the volume of water absorbed by the porous medium = x = 120 ml

Hence, the correct option is (E) 120 ml.
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A mixture comprises water and liquids A and B. The volume of water is 1/3rdof the total mixture and the volume of liquids A and B are in the ratio 5:3. To remove the water, the mixture is passed through a porous medium which completely absorbs the water and partially absorbs liquid A. Altogether this porous medium absorbs 200 ml of the initial mixture. If the ratio of volume of liquids A and B in the residual concentrated mixture becomes 7:9 then find the volume of water absorbed by the porous medium.a)60 mlb)200/3 mlc)80 mld)100 mle)120 mlCorrect answer is option 'E'. Can you explain this answer?
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