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Three men A, B and C working together can complete the work in 30 days. They start to work together A works for 3days and takes rest on the forth day, B works for 5 days and takes rest on the next two days and C works for 7 days and takes rest for next three days. If A, B and C work on the same rate, in how many days will the work be completed?
Most Upvoted Answer
Three men A, B and C working together can complete the work in 30 days...
Solution:

Given data:
- A works for 3 days and takes rest on the fourth day.
- B works for 5 days and takes rest on the next two days.
- C works for 7 days and takes rest for the next three days.
- A, B and C work together can complete the work in 30 days.

To find:
- In how many days will the work be completed?

Approach:
- Let's assume that the total work is equal to 30 units.
- We will calculate each person's efficiency in one day.
- Then, we will calculate the total work done by each person until they take their rest day.
- After that, we will calculate the remaining work and calculate how many days it will take to complete the remaining work by taking the efficiency of the three persons.

Calculation:
- A, B and C can complete the work in 30 days, so their combined efficiency is 30/30 = 1 unit/day.
- Let's assume that A's efficiency in one day is a units/day, B's efficiency is b units/day and C's efficiency is c units/day.
- So, a+b+c = 1 unit/day (as their combined efficiency is 1 unit/day)
- Now, let's calculate the work done by each person until they take their rest day.
- A works for 3 days, so the work done by A = 3a
- B works for 5 days, so the work done by B = 5b
- C works for 7 days, so the work done by C = 7c
- Total work done by A, B and C together after their rest day:
- A works for 3 days and takes rest on the fourth day, so A works 3 days in 4 days. So, A's efficiency in 4 days = 4a/3 units/day
- B works for 5 days and takes rest on the next two days, so B works 5 days in 7 days. So, B's efficiency in 7 days = 7b/5 units/day
- C works for 7 days and takes rest for the next three days, so C works 7 days in 10 days. So, C's efficiency in 10 days = 10c/7 units/day
- Total work done by A, B and C together in these 10 days = (4a/3 + 7b/5 + 10c/7) * 10 units
- Remaining work:
- Total work = 30 units
- Work done by A, B and C in 10 days = (4a/3 + 7b/5 + 10c/7) * 10 units
- Remaining work = Total work - Work done by A, B and C in 10 days
- Remaining work = 30 - (4a/3 + 7b/5 + 10c/7) * 10 units
- Now, we need to calculate how many days it will take to complete the remaining work by taking the efficiency of the three persons.
- Efficiency of A, B and C together = a+b+c = 1 unit/day
- So, the remaining work will be completed in (Remaining work) / (Efficiency of A, B, and
Community Answer
Three men A, B and C working together can complete the work in 30 days...
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Three men A, B and C working together can complete the work in 30 days. They start to work together A works for 3days and takes rest on the forth day, B works for 5 days and takes rest on the next two days and C works for 7 days and takes rest for next three days. If A, B and C work on the same rate, in how many days will the work be completed?
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