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A tank can be filled by a tap in 10 minutes and by another tap in 30 minutes. Both the taps are kept open for 5 minutes and then the first tap is shut off. After this, the tank, will be filled in what time?
  • a)
    25 minutes
  • b)
    15 minutes
  • c)
    10 minutes
  • d)
    20 minutes
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A tank can be filled by a tap in 10 minutes and by another tap in 30 m...
GIVEN:
Tap A fill the tank in 10 minutes and Tap B fill the tank in 30 minutes
FORMULA USED:
Remaining work = 1 - (A + B)’s 5-minute work
CALCULATION:
Part filled by Tap A in 1 minute = 1/10
Part filled by Tap B in 1 minute = 1/30
(A + B)’s 5-minute work = 5 × (1/10 + 1/30)
= 5 × ((3 + 1)/30)
= 5 × (4/30)
= 2/3
Remaining work = 1 - 2/3 = 1/3
1/30th Part filled by Tap B in = 1 minute
1/3rd Part will be filled in = (1/3)/(1/30)
= 30/3
= 10 minutes
Alternate method:
Let total capacity of tank = LCM of (10, 30) = 30 L
So, A can fill in 1 minute = 30/10 = 3L and B can fill in 1 minute = 30/30 = 1L
So, both taps together filled in 5 minutes = (3 + 1) × 5 = 4 × 5 = 20 L
So remaining tank = 30 - 20 = 10
So this 10L is completed filled by B tap = 10/1 = 10 minutes
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Most Upvoted Answer
A tank can be filled by a tap in 10 minutes and by another tap in 30 m...
To solve this problem, we can use the concept of rates. Let's say the first tap can fill the tank at a rate of 1 unit per minute, and the second tap can fill the tank at a rate of 1/3 units per minute.

First Scenario: Both taps are open for 5 minutes
In this scenario, both taps are open for 5 minutes, so we need to calculate the amount of water filled by both taps in 5 minutes.

- The first tap can fill the tank at a rate of 1 unit per minute, so in 5 minutes, it will fill 5 units of water.
- The second tap can fill the tank at a rate of 1/3 units per minute, so in 5 minutes, it will fill (5/3) units of water.

Therefore, in the first scenario, the tank will be filled with a total of (5 + 5/3) units of water.

Second Scenario: First tap is shut off
After 5 minutes, the first tap is shut off, and only the second tap is open. Now we need to calculate the time it takes for the second tap to fill the remaining portion of the tank.

- The second tap can fill the tank at a rate of 1/3 units per minute.
- The remaining portion of the tank to be filled is (1 - 5 - 5/3) units.

Let's denote the time taken by the second tap to fill the remaining portion as T.

Therefore, according to the formula of rate * time = work done, we can write the equation:

(1/3) * T = (1 - 5 - 5/3)

Simplifying the equation, we get:

T = 3(1 - 5 - 5/3)

T = 3(3/3 - 15/3 - 5/3)

T = 3(-17/3)

T = -17 minutes

Since time cannot be negative, we discard the negative value and take the absolute value.

Therefore, the time taken by the second tap to fill the remaining portion is 17 minutes.

Final Answer:
The tank will be filled in a total time of (5 + 5/3 + 17) minutes, which is equal to 10 minutes.
Thus, the correct answer is option 'C': 10 minutes.
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A tank can be filled by a tap in 10 minutes and by another tap in 30 minutes. Both the taps are kept open for 5 minutes and then the first tap is shut off. After this, the tank, will be filled in what time?a)25 minutesb)15 minutesc)10 minutesd)20 minutesCorrect answer is option 'C'. Can you explain this answer?
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