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In wheatstone's network P=2 ohm ,Q=2 ohm R=2ohm and S=3 ohm.The resistance with which s is to shunted in order that the bridge may be balanced is?
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In wheatstone's network P=2 ohm ,Q=2 ohm R=2ohm and S=3 ohm.The resist...
Solution:

Given, P=2 ohm, Q=2 ohm, R=2 ohm, and S=3 ohm

To balance the wheatstone bridge network, the condition is that the potential difference across the bridge should be zero.

Let the unknown resistance which needs to be added to balance the network be x.

Now, the potential difference across the bridge can be written as:

(P/Q) = (x/S+R+x)

2/2 = x/(3+x)

2(3+x) = 2x

6 + 2x = 2x

6 = 0

This is an invalid equation, which means that there is no such resistance that can be added to balance the bridge network.

Hence, the answer is that the resistance with which S is to be shunted in order that the bridge may be balanced does not exist.

Note: The wheatstone bridge network is used to measure the unknown resistance by comparing it with a known resistance. If the bridge is not balanced, it indicates that the unknown resistance is not equal to the known resistance. In such a case, the resistance with which S is to be shunted can be calculated using the formula: x = (S*R)/Q where x is the shunt resistance. But in this case, the bridge cannot be balanced with any resistance.
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In wheatstone's network P=2 ohm ,Q=2 ohm R=2ohm and S=3 ohm.The resist...
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In wheatstone's network P=2 ohm ,Q=2 ohm R=2ohm and S=3 ohm.The resistance with which s is to shunted in order that the bridge may be balanced is?
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