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Resistance of 0.2 M solution of an electrolyte is 50 Ω The specific conductance of the solution is 1.3 Sm-1. If resistance of the 0.4 M solution of the same electrolyte is 260 Ω, its molar conductivity is
(AIEEE 2011)
- a)6250 S m2 mol-1
- b)6.25 x 10-4 S m2 mol-1
- c)625 x 10-4 S m2 mol-1
- d)62.5 x 10-4 S m2 mol-1
Correct answer is option 'B'. Can you explain this answer?
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Resistance of 0.2 M solution of an electrolyte is 50 The specific con...
Molar conductivity of the solution is given by
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Resistance of 0.2 M solution of an electrolyte is 50 The specific con...
To find the molar conductivity of the 0.4 M solution of the electrolyte, we can use the relationship between specific conductance and molar conductivity.
The specific conductance (κ) is defined as the conductance of a solution of unit volume (1 m^3) and unit length (1 m) with electrodes of unit area (1 m^2) placed 1 m apart. The specific conductance can be calculated using the formula:
κ = G / (A * l)
Where:
κ is the specific conductance
G is the conductance of the solution
A is the area of the electrodes
l is the distance between the electrodes
In this case, the specific conductance of the 0.2 M solution is given as 1.3 S m^-1, and the resistance is given as 50 Ω. We can calculate the conductance using the formula:
G = 1 / R
Where:
G is the conductance
R is the resistance
Substituting the given values, we get:
G = 1 / 50 = 0.02 S
Now, we can calculate the molar conductivity (Λ) using the formula:
Λ = κ / c
Where:
Λ is the molar conductivity
κ is the specific conductance
c is the concentration of the electrolyte
For the 0.2 M solution, the molar conductivity can be calculated as:
Λ = 1.3 / 0.2 = 6.5 S m^2 mol^-1
Now, let's find the resistance of the 0.4 M solution. It is given as 260 Ω. We can calculate the conductance using the formula:
G = 1 / R = 1 / 260 = 0.003846 S
Finally, we can calculate the molar conductivity of the 0.4 M solution using the formula:
Λ = κ / c = 0.003846 / 0.4 = 0.009615 S m^2 mol^-1
Therefore, the molar conductivity of the 0.4 M solution is approximately 0.009615 S m^2 mol^-1, which is equivalent to option B: 6.25 x 10^-4 S m^2 mol^-1.
The specific conductance (κ) is defined as the conductance of a solution of unit volume (1 m^3) and unit length (1 m) with electrodes of unit area (1 m^2) placed 1 m apart. The specific conductance can be calculated using the formula:
κ = G / (A * l)
Where:
κ is the specific conductance
G is the conductance of the solution
A is the area of the electrodes
l is the distance between the electrodes
In this case, the specific conductance of the 0.2 M solution is given as 1.3 S m^-1, and the resistance is given as 50 Ω. We can calculate the conductance using the formula:
G = 1 / R
Where:
G is the conductance
R is the resistance
Substituting the given values, we get:
G = 1 / 50 = 0.02 S
Now, we can calculate the molar conductivity (Λ) using the formula:
Λ = κ / c
Where:
Λ is the molar conductivity
κ is the specific conductance
c is the concentration of the electrolyte
For the 0.2 M solution, the molar conductivity can be calculated as:
Λ = 1.3 / 0.2 = 6.5 S m^2 mol^-1
Now, let's find the resistance of the 0.4 M solution. It is given as 260 Ω. We can calculate the conductance using the formula:
G = 1 / R = 1 / 260 = 0.003846 S
Finally, we can calculate the molar conductivity of the 0.4 M solution using the formula:
Λ = κ / c = 0.003846 / 0.4 = 0.009615 S m^2 mol^-1
Therefore, the molar conductivity of the 0.4 M solution is approximately 0.009615 S m^2 mol^-1, which is equivalent to option B: 6.25 x 10^-4 S m^2 mol^-1.
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Resistance of 0.2 M solution of an electrolyte is 50 The specific conductance of the solution is 1.3 Sm-1. If resistance of the 0.4 M solution of the same electrolyte is 260 , its molar conductivity is(AIEEE2011)a)6250 S m2mol-1b)6.25 x 10-4S m2mol-1c)625 x 10-4S m2mol-1d)62.5 x 10-4S m2mol-1Correct answer is option 'B'. Can you explain this answer?
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Resistance of 0.2 M solution of an electrolyte is 50 The specific conductance of the solution is 1.3 Sm-1. If resistance of the 0.4 M solution of the same electrolyte is 260 , its molar conductivity is(AIEEE2011)a)6250 S m2mol-1b)6.25 x 10-4S m2mol-1c)625 x 10-4S m2mol-1d)62.5 x 10-4S m2mol-1Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Resistance of 0.2 M solution of an electrolyte is 50 The specific conductance of the solution is 1.3 Sm-1. If resistance of the 0.4 M solution of the same electrolyte is 260 , its molar conductivity is(AIEEE2011)a)6250 S m2mol-1b)6.25 x 10-4S m2mol-1c)625 x 10-4S m2mol-1d)62.5 x 10-4S m2mol-1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Resistance of 0.2 M solution of an electrolyte is 50 The specific conductance of the solution is 1.3 Sm-1. If resistance of the 0.4 M solution of the same electrolyte is 260 , its molar conductivity is(AIEEE2011)a)6250 S m2mol-1b)6.25 x 10-4S m2mol-1c)625 x 10-4S m2mol-1d)62.5 x 10-4S m2mol-1Correct answer is option 'B'. Can you explain this answer?.
Resistance of 0.2 M solution of an electrolyte is 50 The specific conductance of the solution is 1.3 Sm-1. If resistance of the 0.4 M solution of the same electrolyte is 260 , its molar conductivity is(AIEEE2011)a)6250 S m2mol-1b)6.25 x 10-4S m2mol-1c)625 x 10-4S m2mol-1d)62.5 x 10-4S m2mol-1Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Resistance of 0.2 M solution of an electrolyte is 50 The specific conductance of the solution is 1.3 Sm-1. If resistance of the 0.4 M solution of the same electrolyte is 260 , its molar conductivity is(AIEEE2011)a)6250 S m2mol-1b)6.25 x 10-4S m2mol-1c)625 x 10-4S m2mol-1d)62.5 x 10-4S m2mol-1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Resistance of 0.2 M solution of an electrolyte is 50 The specific conductance of the solution is 1.3 Sm-1. If resistance of the 0.4 M solution of the same electrolyte is 260 , its molar conductivity is(AIEEE2011)a)6250 S m2mol-1b)6.25 x 10-4S m2mol-1c)625 x 10-4S m2mol-1d)62.5 x 10-4S m2mol-1Correct answer is option 'B'. Can you explain this answer?.
Solutions for Resistance of 0.2 M solution of an electrolyte is 50 The specific conductance of the solution is 1.3 Sm-1. If resistance of the 0.4 M solution of the same electrolyte is 260 , its molar conductivity is(AIEEE2011)a)6250 S m2mol-1b)6.25 x 10-4S m2mol-1c)625 x 10-4S m2mol-1d)62.5 x 10-4S m2mol-1Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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