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Resistance of 0.2 M solution of an electrolyte is 50 Ω. The specific conductance of the solution is 1.4 Sm-1. The resistance of 0.5 M solution of the same electrolyte is 280 Ω The molar conductivity of 0.5 Msolution of the electrolyte in S mol-1 is
(JEE Main 2014)
- a)5 x 10-4
- b)5 x 10-3
- c)5 x 103
- d)5 x 102
Correct answer is option 'A'. Can you explain this answer?
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Resistance of 0.2 M solution of an electrolyte is 50 . The specific co...
The resistivity of the solution is related to specific conductance by
The specific conductance of the solution is given by
Now, the molar conductivity of the solution is given by
Hence, the molar conductivity of 0.5 M solution of the electrolyte is 5 x 10 -4 S m2 mol-1.
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Resistance of 0.2 M solution of an electrolyte is 50 . The specific co...
Given:
Resistance of 0.2 M solution of the electrolyte = 50 Ω
Specific conductance of the solution = 1.4 S m^-1
Resistance of 0.5 M solution of the electrolyte = 280 Ω
To find: Molar conductivity of 0.5 M solution of the electrolyte
Formula used:
Specific conductance (κ) = Conductivity (σ) / Concentration (C)
Molar conductivity (Λ) = κ / C
Calculation:
1. Calculate the specific conductance of the 0.2 M solution.
κ = 1.4 S m^-1
2. Calculate the conductivity of the 0.2 M solution.
Conductivity (σ) = κ * Concentration (C)
σ = 1.4 S m^-1 * 0.2 mol m^-3
σ = 0.28 S m^-1
3. Calculate the resistance of the 0.2 M solution.
Resistance (R) = 50 Ω
4. Calculate the cell constant (k) using the resistance and conductivity.
k = σ / R
k = 0.28 S m^-1 / 50 Ω
k = 0.0056 m^2 S^-1
5. Calculate the specific conductance of the 0.5 M solution using the cell constant.
Specific conductance (κ) = k * Concentration (C)
κ = 0.0056 m^2 S^-1 * 0.5 mol m^-3
κ = 0.0028 S m^-1
6. Calculate the molar conductivity of the 0.5 M solution using the specific conductance.
Molar conductivity (Λ) = κ / C
Λ = 0.0028 S m^-1 / 0.5 mol m^-3
Λ = 0.0056 S m^2 mol^-1
Therefore, the molar conductivity of the 0.5 M solution of the electrolyte is 0.0056 S m^2 mol^-1, which is equivalent to 5 x 10^-4 S mol^-1. Hence, option A is the correct answer.
Resistance of 0.2 M solution of the electrolyte = 50 Ω
Specific conductance of the solution = 1.4 S m^-1
Resistance of 0.5 M solution of the electrolyte = 280 Ω
To find: Molar conductivity of 0.5 M solution of the electrolyte
Formula used:
Specific conductance (κ) = Conductivity (σ) / Concentration (C)
Molar conductivity (Λ) = κ / C
Calculation:
1. Calculate the specific conductance of the 0.2 M solution.
κ = 1.4 S m^-1
2. Calculate the conductivity of the 0.2 M solution.
Conductivity (σ) = κ * Concentration (C)
σ = 1.4 S m^-1 * 0.2 mol m^-3
σ = 0.28 S m^-1
3. Calculate the resistance of the 0.2 M solution.
Resistance (R) = 50 Ω
4. Calculate the cell constant (k) using the resistance and conductivity.
k = σ / R
k = 0.28 S m^-1 / 50 Ω
k = 0.0056 m^2 S^-1
5. Calculate the specific conductance of the 0.5 M solution using the cell constant.
Specific conductance (κ) = k * Concentration (C)
κ = 0.0056 m^2 S^-1 * 0.5 mol m^-3
κ = 0.0028 S m^-1
6. Calculate the molar conductivity of the 0.5 M solution using the specific conductance.
Molar conductivity (Λ) = κ / C
Λ = 0.0028 S m^-1 / 0.5 mol m^-3
Λ = 0.0056 S m^2 mol^-1
Therefore, the molar conductivity of the 0.5 M solution of the electrolyte is 0.0056 S m^2 mol^-1, which is equivalent to 5 x 10^-4 S mol^-1. Hence, option A is the correct answer.
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Resistance of 0.2 M solution of an electrolyte is 50 . The specific conductance of the solution is 1.4 Sm-1. The resistance of 0.5 M solution of the same electrolyte is 280 The molar conductivity of 0.5 Msolution of the electrolyte in S mol-1 is(JEE Main 2014)a)5 x 10-4b)5 x 10-3c)5 x 103d)5 x 102Correct answer is option 'A'. Can you explain this answer?
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Resistance of 0.2 M solution of an electrolyte is 50 . The specific conductance of the solution is 1.4 Sm-1. The resistance of 0.5 M solution of the same electrolyte is 280 The molar conductivity of 0.5 Msolution of the electrolyte in S mol-1 is(JEE Main 2014)a)5 x 10-4b)5 x 10-3c)5 x 103d)5 x 102Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Resistance of 0.2 M solution of an electrolyte is 50 . The specific conductance of the solution is 1.4 Sm-1. The resistance of 0.5 M solution of the same electrolyte is 280 The molar conductivity of 0.5 Msolution of the electrolyte in S mol-1 is(JEE Main 2014)a)5 x 10-4b)5 x 10-3c)5 x 103d)5 x 102Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Resistance of 0.2 M solution of an electrolyte is 50 . The specific conductance of the solution is 1.4 Sm-1. The resistance of 0.5 M solution of the same electrolyte is 280 The molar conductivity of 0.5 Msolution of the electrolyte in S mol-1 is(JEE Main 2014)a)5 x 10-4b)5 x 10-3c)5 x 103d)5 x 102Correct answer is option 'A'. Can you explain this answer?.
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Solutions for Resistance of 0.2 M solution of an electrolyte is 50 . The specific conductance of the solution is 1.4 Sm-1. The resistance of 0.5 M solution of the same electrolyte is 280 The molar conductivity of 0.5 Msolution of the electrolyte in S mol-1 is(JEE Main 2014)a)5 x 10-4b)5 x 10-3c)5 x 103d)5 x 102Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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ample number of questions to practice Resistance of 0.2 M solution of an electrolyte is 50 . The specific conductance of the solution is 1.4 Sm-1. The resistance of 0.5 M solution of the same electrolyte is 280 The molar conductivity of 0.5 Msolution of the electrolyte in S mol-1 is(JEE Main 2014)a)5 x 10-4b)5 x 10-3c)5 x 103d)5 x 102Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
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