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Robot is 4 m in length and placed at a corner of a 16 m × 30 m field. The robot is facing a diagonally opposite corner and reaches the diagonally opposite corner in 15 s. What is the speed (in m/s) of a robot?
- a)5
- b)2
- c)3
- d)1
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Robot is 4 m in length and placed at a corner of a 16 m × 30 m field....
To find the speed of the robot, we need to determine the distance it travels and the time it takes to cover that distance.
Distance:
The robot starts at one corner of the field and reaches the diagonally opposite corner. We can consider this as the length of the field. Given that the field is 16 m wide and 30 m long, the distance the robot needs to cover is the length of the field's diagonal.
Using the Pythagorean theorem, we can find the length of the diagonal:
d^2 = 16^2 + 30^2
d^2 = 256 + 900
d^2 = 1156
d = √1156
d = 34 m
Therefore, the distance the robot travels is 34 m.
Time:
The robot takes 15 seconds to cover the distance.
Speed:
To find the speed, we use the formula: speed = distance/time.
Plugging in the values:
speed = 34 m / 15 s
speed = 2.27 m/s (rounded to two decimal places)
Therefore, the speed of the robot is approximately 2.27 m/s.
So, the correct answer is option B) 2.
Distance:
The robot starts at one corner of the field and reaches the diagonally opposite corner. We can consider this as the length of the field. Given that the field is 16 m wide and 30 m long, the distance the robot needs to cover is the length of the field's diagonal.
Using the Pythagorean theorem, we can find the length of the diagonal:
d^2 = 16^2 + 30^2
d^2 = 256 + 900
d^2 = 1156
d = √1156
d = 34 m
Therefore, the distance the robot travels is 34 m.
Time:
The robot takes 15 seconds to cover the distance.
Speed:
To find the speed, we use the formula: speed = distance/time.
Plugging in the values:
speed = 34 m / 15 s
speed = 2.27 m/s (rounded to two decimal places)
Therefore, the speed of the robot is approximately 2.27 m/s.
So, the correct answer is option B) 2.
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Community Answer
Robot is 4 m in length and placed at a corner of a 16 m × 30 m field....
ABCD is rectangle. Then, ∠B = 90°
Using the Pythagorean Theorem:
AC = √256 + √900 = √1156 = 34
Length of the Robot = 4 m.
Travelled distance by the Robot = 34 – 4 = 30 m
Speed of the Robot = 30/15 = 2 m/s
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Robot is 4 m in length and placed at a corner of a 16 m × 30 m field. The robot is facing a diagonally opposite corner and reaches the diagonally opposite corner in 15 s. What is the speed (in m/s) of a robot?a) 5b) 2c) 3d) 1Correct answer is option 'B'. Can you explain this answer?
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