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AD is diameter of a circle and AB is a chord. If AD = 50 cm, AB = 48 cm, then the distance of AB from the centre of the circle is
  • a)
    6 cm
  • b)
    8 cm
  • c)
    5 cm
  • d)
    7 cm
Correct answer is option 'D'. Can you explain this answer?
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AD is diameter of a circle and AB is a chord. If AD = 50 cm, AB = 48 c...
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AD is diameter of a circle and AB is a chord. If AD = 50 cm, AB = 48 c...
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AD is diameter of a circle and AB is a chord. If AD = 50 cm, AB = 48 c...
Given information:
- AD is the diameter of the circle, and its length is 50 cm.
- AB is a chord of the circle, and its length is 48 cm.

To find the distance of AB from the center of the circle, we can use the following formula:

Distance of chord from the center = √(r^2 - (d/2)^2)

where r is the radius of the circle and d is the length of the chord.

Step 1: Finding the radius
- The diameter AD is given as 50 cm.
- The formula for the diameter is D = 2r, where D is the length of the diameter and r is the radius.
- Substituting the given value, we have 50 = 2r.
- Dividing both sides by 2, we get r = 25 cm.

Step 2: Finding the distance of AB from the center
- Substituting the values of r and d into the formula, we have
Distance of AB from the center = √(25^2 - (48/2)^2)
= √(625 - 24^2)
= √(625 - 576)
= √49
= 7 cm.

Therefore, the distance of AB from the center of the circle is 7 cm. Hence, option D is the correct answer.
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