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Aluminium oxide may be electrolysed at 1270 K to form Al metal (atomic mass = 27 u, 1F = 96500 C)  
To prepare 5.12 kg of Al metal by this method,it would require
  • a)
    5.49 x 102 C of electricity
  • b)
    5.49 x 104 C of electricity
  • c)
    1.87 x 107 C of electricity
  • d)
    5.49 x 107 C of electricity
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Aluminium oxide may be electrolysed at 1270 K to form Al metal (atomic...
By Faraday’s first law,
w(amount) = zit = zQ
where, it = Q = quantity of electricity
z = electrochemical equivalent 
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Aluminium oxide may be electrolysed at 1270 K to form Al metal (atomic mass = 27 u, 1F = 96500 C) To prepare 5.12 kg of Almetalby this method,it would requirea)5.49 x 102C of electricityb)5.49 x 104C of electricityc)1.87x 107C of electricityd)5.49 x 107C of electricityCorrect answer is option 'C'. Can you explain this answer?
Question Description
Aluminium oxide may be electrolysed at 1270 K to form Al metal (atomic mass = 27 u, 1F = 96500 C) To prepare 5.12 kg of Almetalby this method,it would requirea)5.49 x 102C of electricityb)5.49 x 104C of electricityc)1.87x 107C of electricityd)5.49 x 107C of electricityCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Aluminium oxide may be electrolysed at 1270 K to form Al metal (atomic mass = 27 u, 1F = 96500 C) To prepare 5.12 kg of Almetalby this method,it would requirea)5.49 x 102C of electricityb)5.49 x 104C of electricityc)1.87x 107C of electricityd)5.49 x 107C of electricityCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Aluminium oxide may be electrolysed at 1270 K to form Al metal (atomic mass = 27 u, 1F = 96500 C) To prepare 5.12 kg of Almetalby this method,it would requirea)5.49 x 102C of electricityb)5.49 x 104C of electricityc)1.87x 107C of electricityd)5.49 x 107C of electricityCorrect answer is option 'C'. Can you explain this answer?.
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