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two projectiles are thrown from the same point simultaneously with same velocity 10m/s .one goes straight vertically while other at 60 degree with the vertical. what will be the distance of separation between the two after 1 second of their throw
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two projectiles are thrown from the same point simultaneously with sam...
Problem:

Two projectiles are thrown from the same point simultaneously with the same velocity of 10m/s. One goes straight vertically while the other at 60 degrees with the vertical. What will be the distance of separation between the two after 1 second of their throw?


Solution:

Given, initial velocity (u) = 10m/s, time (t) = 1s


For the projectile thrown vertically:

Using the formula of motion, we can find the displacement of the projectile thrown vertically in 1 second.

Displacement (S) = ut + 1/2at^2

Here, acceleration (a) = -9.8m/s^2 (negative because of the direction of gravity)

Putting the values, we get:

S = (10m/s) x (1s) + 1/2 x (-9.8m/s^2) x (1s)^2

S = 5.1m (approx)


For the projectile thrown at 60 degrees:

We can find the horizontal and vertical components of the velocity using trigonometry.

Horizontal component (u cos 60) = 5m/s

Vertical component (u sin 60) = 8.66m/s

For horizontal motion, the acceleration is zero. So, the displacement is:

S = ut

S = (5m/s) x (1s)

S = 5m

For vertical motion, using the same formula of motion:

S = ut + 1/2at^2

S = (8.66m/s) x (1s) + 1/2 x (-9.8m/s^2) x (1s)^2

S = 4.02m (approx)


Distance of separation:

The distance of separation between the two projectiles is the horizontal distance between them, which is 5m.


Final Answer:

The distance of separation between the two projectiles after 1 second of their throw is 5m.
Community Answer
two projectiles are thrown from the same point simultaneously with sam...
Answer may be 5√3
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