two projectiles are thrown from the same point simultaneously with sam...
Problem:
Two projectiles are thrown from the same point simultaneously with the same velocity of 10m/s. One goes straight vertically while the other at 60 degrees with the vertical. What will be the distance of separation between the two after 1 second of their throw?
Solution:
Given, initial velocity (u) = 10m/s, time (t) = 1s
For the projectile thrown vertically:
Using the formula of motion, we can find the displacement of the projectile thrown vertically in 1 second.
Displacement (S) = ut + 1/2at^2
Here, acceleration (a) = -9.8m/s^2 (negative because of the direction of gravity)
Putting the values, we get:
S = (10m/s) x (1s) + 1/2 x (-9.8m/s^2) x (1s)^2
S = 5.1m (approx)
For the projectile thrown at 60 degrees:
We can find the horizontal and vertical components of the velocity using trigonometry.
Horizontal component (u cos 60) = 5m/s
Vertical component (u sin 60) = 8.66m/s
For horizontal motion, the acceleration is zero. So, the displacement is:
S = ut
S = (5m/s) x (1s)
S = 5m
For vertical motion, using the same formula of motion:
S = ut + 1/2at^2
S = (8.66m/s) x (1s) + 1/2 x (-9.8m/s^2) x (1s)^2
S = 4.02m (approx)
Distance of separation:
The distance of separation between the two projectiles is the horizontal distance between them, which is 5m.
Final Answer:
The distance of separation between the two projectiles after 1 second of their throw is 5m.