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2. An iron sphere of 1kg is moving a velocity of 20 m/s on a cemented floor. It comes to rest after traveling a distance of 50 m. Find the force of friction between the sphere and the floor. of Iriction?
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2. An iron sphere of 1kg is moving a velocity of 20 m/s on a cemented ...
Mass of sphere, m = 1kg
Initial velocity, u = 20 m/s
Final velocity, v = 0
Distance travelled, s = 50m
Let the friction acting = f 
Here, the kinetic energy of the ball is being dissipated to overcome friction. So, according to conservation of energy,
The change in kinetic energy = work done by friction

So friction acting is 4N. The negative sign denotes that it acts in the direction opposite to the motion of the sphere.

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2. An iron sphere of 1kg is moving a velocity of 20 m/s on a cemented ...
Force of Friction between the Sphere and the Floor

Given:
Mass of the iron sphere (m) = 1 kg
Initial velocity of the sphere (u) = 20 m/s
Distance traveled by the sphere (s) = 50 m

To find:
Force of friction between the sphere and the floor (Ff)

Using the kinematic equation:
v^2 = u^2 + 2as

where v is the final velocity and a is the acceleration.

First, let's find the final velocity (v) of the sphere when it comes to rest. Since it comes to rest, the final velocity is 0 m/s.

0 = (20 m/s)^2 + 2a(50 m)
0 = 400 m^2/s^2 + 100a m
a = -400/100 = -4 m/s^2

The negative sign indicates that the acceleration is in the opposite direction to the initial velocity, which is due to the force of friction acting against the motion of the sphere.

Using Newton's second law of motion:
F = ma

where F is the force, m is the mass, and a is the acceleration.

The force of friction (Ff) is given by:
Ff = μN

where μ is the coefficient of friction and N is the normal force.

Since the sphere is on a horizontal surface, the normal force is equal to the weight of the sphere (N = mg).

Let's assume the coefficient of friction between the iron sphere and the cemented floor is μ.

Ff = μN
Ff = μmg

Now, substituting the values:
Ff = μ(1 kg)(9.8 m/s^2)
Ff = 9.8μ N

So, the force of friction between the iron sphere and the floor is 9.8μ Newtons.

Explanation:
- The force of friction between the sphere and the floor causes the sphere to slow down and eventually come to rest.
- The force of friction is directly proportional to the normal force and the coefficient of friction.
- The normal force is the force exerted by the floor on the sphere in the vertical direction and is equal to the weight of the sphere.
- The coefficient of friction represents the roughness or smoothness of the surfaces in contact.
- The negative acceleration indicates that the sphere is decelerating or slowing down.
- The force of friction always acts in the opposite direction to the motion of the object.
- In this case, the force of friction opposes the motion of the sphere, causing it to slow down and eventually come to rest.
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2. An iron sphere of 1kg is moving a velocity of 20 m/s on a cemented floor. It comes to rest after traveling a distance of 50 m. Find the force of friction between the sphere and the floor. of Iriction?
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