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You have two C6H10O ketones, I and II. Both are optically active, but I is racemised by treatment with base and II is not. Wolff-Kishner reduction of both ketones give the same achiral hydrocarbon, formula C6H12. What reasonable structures may be assigned to I and II?a)I is 3-methyl-4-penten-2-one; II is 4-methyl-1-penten-3-oneb)I is 2-methyl cyclopentanone; II is 3-methyi cyclopentanonec)I is 3-methyl cyclopentanone; II is 2-methyl cyclopentanoned)I is 2-ethyl cyclobutanone; II is 3-ethyl cyclobutanoneCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
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the JEE exam syllabus. Information about You have two C6H10O ketones, I and II. Both are optically active, but I is racemised by treatment with base and II is not. Wolff-Kishner reduction of both ketones give the same achiral hydrocarbon, formula C6H12. What reasonable structures may be assigned to I and II?a)I is 3-methyl-4-penten-2-one; II is 4-methyl-1-penten-3-oneb)I is 2-methyl cyclopentanone; II is 3-methyi cyclopentanonec)I is 3-methyl cyclopentanone; II is 2-methyl cyclopentanoned)I is 2-ethyl cyclobutanone; II is 3-ethyl cyclobutanoneCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for You have two C6H10O ketones, I and II. Both are optically active, but I is racemised by treatment with base and II is not. Wolff-Kishner reduction of both ketones give the same achiral hydrocarbon, formula C6H12. What reasonable structures may be assigned to I and II?a)I is 3-methyl-4-penten-2-one; II is 4-methyl-1-penten-3-oneb)I is 2-methyl cyclopentanone; II is 3-methyi cyclopentanonec)I is 3-methyl cyclopentanone; II is 2-methyl cyclopentanoned)I is 2-ethyl cyclobutanone; II is 3-ethyl cyclobutanoneCorrect answer is option 'B'. Can you explain this answer?.
Solutions for You have two C6H10O ketones, I and II. Both are optically active, but I is racemised by treatment with base and II is not. Wolff-Kishner reduction of both ketones give the same achiral hydrocarbon, formula C6H12. What reasonable structures may be assigned to I and II?a)I is 3-methyl-4-penten-2-one; II is 4-methyl-1-penten-3-oneb)I is 2-methyl cyclopentanone; II is 3-methyi cyclopentanonec)I is 3-methyl cyclopentanone; II is 2-methyl cyclopentanoned)I is 2-ethyl cyclobutanone; II is 3-ethyl cyclobutanoneCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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Here you can find the meaning of You have two C6H10O ketones, I and II. Both are optically active, but I is racemised by treatment with base and II is not. Wolff-Kishner reduction of both ketones give the same achiral hydrocarbon, formula C6H12. What reasonable structures may be assigned to I and II?a)I is 3-methyl-4-penten-2-one; II is 4-methyl-1-penten-3-oneb)I is 2-methyl cyclopentanone; II is 3-methyi cyclopentanonec)I is 3-methyl cyclopentanone; II is 2-methyl cyclopentanoned)I is 2-ethyl cyclobutanone; II is 3-ethyl cyclobutanoneCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
You have two C6H10O ketones, I and II. Both are optically active, but I is racemised by treatment with base and II is not. Wolff-Kishner reduction of both ketones give the same achiral hydrocarbon, formula C6H12. What reasonable structures may be assigned to I and II?a)I is 3-methyl-4-penten-2-one; II is 4-methyl-1-penten-3-oneb)I is 2-methyl cyclopentanone; II is 3-methyi cyclopentanonec)I is 3-methyl cyclopentanone; II is 2-methyl cyclopentanoned)I is 2-ethyl cyclobutanone; II is 3-ethyl cyclobutanoneCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for You have two C6H10O ketones, I and II. Both are optically active, but I is racemised by treatment with base and II is not. Wolff-Kishner reduction of both ketones give the same achiral hydrocarbon, formula C6H12. What reasonable structures may be assigned to I and II?a)I is 3-methyl-4-penten-2-one; II is 4-methyl-1-penten-3-oneb)I is 2-methyl cyclopentanone; II is 3-methyi cyclopentanonec)I is 3-methyl cyclopentanone; II is 2-methyl cyclopentanoned)I is 2-ethyl cyclobutanone; II is 3-ethyl cyclobutanoneCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of You have two C6H10O ketones, I and II. Both are optically active, but I is racemised by treatment with base and II is not. Wolff-Kishner reduction of both ketones give the same achiral hydrocarbon, formula C6H12. What reasonable structures may be assigned to I and II?a)I is 3-methyl-4-penten-2-one; II is 4-methyl-1-penten-3-oneb)I is 2-methyl cyclopentanone; II is 3-methyi cyclopentanonec)I is 3-methyl cyclopentanone; II is 2-methyl cyclopentanoned)I is 2-ethyl cyclobutanone; II is 3-ethyl cyclobutanoneCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice You have two C6H10O ketones, I and II. Both are optically active, but I is racemised by treatment with base and II is not. Wolff-Kishner reduction of both ketones give the same achiral hydrocarbon, formula C6H12. What reasonable structures may be assigned to I and II?a)I is 3-methyl-4-penten-2-one; II is 4-methyl-1-penten-3-oneb)I is 2-methyl cyclopentanone; II is 3-methyi cyclopentanonec)I is 3-methyl cyclopentanone; II is 2-methyl cyclopentanoned)I is 2-ethyl cyclobutanone; II is 3-ethyl cyclobutanoneCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.